All categories

3 years ago

Evaluate -6-2x when x=-4

Mathematics

1 answer:

ad-work [718]3 years ago

8 0

Answer:

Step-by-step explanation:

Given $-6-2x$ where $x=-4$ , substitute $x=-4$ to find the value of the given equation.

Substituting $x=-4$ :

$-6-2(-4)$

Multiply $-2\cdot -4$ :

$-6+8$

Combine like terms:

$-6+8=\boxed{2}$

Therefore, the value of $-6-2x$ when $x=-4$ is $\boxed{2}$ .

You might be interested in

Find two positive consecutive odd integers such that the square of the large integer is one less than twice the square of the sm

andre [41]

Step-by-step explanation:

x, x+2 are the two positive consecutive of integers (x + 2, because the minimum distance between 2 odd numbers is always 2, as there can never be 2 odd numbers directly following each other; and neither can even numbers, by the way).

(x+2)² = 2×x² - 1

x² + 4x + 4 = 2x² - 1

0 = x² - 4x - 5

we can solve this by factoring.

that means we need to find a and b so that

(x - a)(x - b) = x² - 4x - 5 = 0

and x = a and x = b are the 2 solutions of the quadratic equation.

x² - ax - bx + ab = x² - 4x - 5 = 0

x² - (a+b)x + ab = x² - 4x - 5 = 0

a+b = 4

ab = -5

that means that either a or b has to be 5 and the other -1.

so, the result is

(x - 5)(x + 1) = 0

x = 5

x = -1

are the possible solutions.

since we are only looking for positive integers, x = -1 is not a valid solution.

and only x = 5 remains as valid solution.

therefore, the 2 positive consecutive odd integers are

5, 7

4 0

2 years ago

A rectangle is 2/5 in. long and 1/3 in. wide. What is the area of the rectangle?

Aloiza [94]

The area of the rectangle is 1/3 * 2/5=2/15 inches
please mark as brainliest

7 0

3 years ago

Read 2 more answers

The blue are the two boards that you need to use.

ad-work [718]

Answer:

for what?

Step-by-step explanation:

7 0

3 years ago

I need some help on these 3 questions :)

wlad13 [49]

The factor of the polynomial, the area of the pool and the simplified expression are all algebraic expressions

<h3>How to simplify the expressions?</h3>

Factor of the polynomial

The polynomial is given as:

2x^3 + 6x^2 + 6x + 18

Factor out 2

2x^3 + 6x^2 + 6x + 18 = 2(x^3 + 3x^2 + 3x + 9)

Factorize

2x^3 + 6x^2 + 6x + 18 = 2(x^2(x + 3) + 3(x + 3))

Factor out x + 3

2x^3 + 6x^2 + 6x + 18 = 2(x^2 + 3)(x + 3)

Expand

2x^3 + 6x^2 + 6x + 18 = (2x^2 + 6)(x + 3)

Hence, 2x^2 + 6 is a factor of the polynomial 2x^3 + 6x^2 + 6x + 18

The length of the pool

The given parameters are:

Area = 2x^3 - 29x + 12

Width = x + 4

The length is calculated as:

Length = Area/Width

This gives

Length = 2x^2 - 29x + 12/x + 4

Factorize the numerator

Length = (2x^2 - 8x + 3)(x + 4)/x + 4

Cancel out x + 4

Length = 2x^2 - 8x + 3

Hence, the length of the pool is 2x^2 - 8x + 3

Simplify the expression

The expression is given as:

(3s^2 - 2s + 1) $\div$ (s^2 - s + 2)

Evaluate the quotient

3 + (s - 5)/(s^2 - 5 + 2)

Hence, the simplified expression is 3 + (s - 5)/(s^2 - 5 + 2)

Read more about algebraic expressions at:

brainly.com/question/2164351

3 0

2 years ago

Hey i really need help with this. thank you:))

balandron [24]

Given:

$L=2\dfrac{1}{2}$ ft and $W=3\dfrac{2}{5}$ ft.

$P=2L+2W$

To find:

The value of P.

Solution:

We have,

$P=2L+2W$

Substituting $L=2\dfrac{1}{2}$ and $W=3\dfrac{2}{5}$ , we get

$P=2\times 2\dfrac{1}{2}+2\times 3\dfrac{2}{5}$

$P=2\times \dfrac{2(2)+1}{2}+2\times \dfrac{3(5)+2}{5}$

$P=2\times \dfrac{5}{2}+2\times \dfrac{17}{5}$

$P=5+\dfrac{34}{5}$

Taking LCM, we get

$P=\dfrac{5(5)+34}{5}$

$P=\dfrac{25+34}{5}$

$P=\dfrac{59}{5}$

$P=11\dfrac{4}{5}$

Therefore, the value of P is $11\dfrac{4}{5}$ ft.

7 0

3 years ago