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3 years ago

14

Can you help? Find the distance between A(8,3) and B(9,0) to the nearest hundredth.

1 answer:

frez [133]3 years ago

8 0

Answer:

3.16

Step-by-step explanation:

distance = $\sqrt{(8-9)^{2} +(3-0)^{2} }$

= $\sqrt{1^{2} +3^{2} }$

= $\sqrt{1+9}$

= $\sqrt{10}$

=3.16

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24 4/8 - 19 5/8 STEP BY STEP EXPLANATION

Elanso [62]

Answer:

First, in order to subtract these two fractions you must convert it into improper fractions. For the first one, we can convert it by multiplying the denominator by the whole and adding the numerator which would give you 196/8 for the first one and 157/8 for the second one. This equation would now set up as 196/8-157/8 which would be 39/8 and since you need to convert it back into a mixed fraction we need to know how many times 8 can go into 39 which is 4 so 32 and a remainder of 7. Your answer would be 4 7/8

Step-by-step explanation:

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3 years ago

The capacity of a beaker is 150 mL. How many beakers can be filled from a 4L container?

andrew11 [14]

4000 divided by 150 = 26.7 means 26 containers..
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3 years ago

This is a tricky one<br>n ÷ 9 = 14

PSYCHO15rus [73]

Answer:

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Step-by-step explanation:

3 0

3 years ago

A triangle has one angle that is three times the size of another, and a third angle that is 16degrees smaller than the larger of

Dafna11 [192]

Answer:

26, 68 and 84

Step-by-step explanation:

Let the angle that is three times smaller than another be X.

Since the angle sum of a triangle is 180 degrees, we can form the following equation:

X + 3X + (3X- 16) = 180

Now we can simplify this equation:

7X - 16 = 180

7X = 196 (add 16 to both sides)

X = 196/7

X = 28

Therefore, the smallest angle is 28 degrees.

And from here we can figure out the other angles as they are 3x28 and 3x28 - 16.

So the three angles are 28 degrees, (3x28-16) 68 degrees, and (3x28) 84 degrees.

6 0

3 years ago

Read 2 more answers

6. A super-bouncy-ball is thrown 25m into the air. The ball falls, rebounds to 70% of the height of the previous bounce and fall

inn [45]

Answer:

The total distance the ball has travelled after it hits the ground the 5th time is of 48.53m.

Step-by-step explanation:

Geometric sequence:

In a geometric sequence, the quotient of consecutive terms is the same. The nth term of a geometric sequence is given by:

$a_n = a_1q^{n-1}$

In which $a_1$ is the first term and $q$ is the common ratio.

A super-bouncy-ball is thrown 25m into the air. The ball falls, rebounds to 70% of the height of the previous bounce and falls again.

This means that:

$q = 0.7, a_1 = 25*0.7 = 17.5$

Then

$a_n = a_1q^{n-1}$

$a_n = 17.5(0.7)^{n-1}$

First 5 terms:

$a_1 = 17.5$

$a_2 = 17.5(0.7)^{2-1} = 12.25$

$a_3 = 17.5(0.7)^{3-1} = 8.58$

$a_4 = 17.5(0.7)^{4-1} = 6$

$a_5 = 17.5(0.7)^{5-1} = 4.2$

Find the total distance the ball has travelled after it hits the ground the 5th time.

$T = 17.5 + 12.25 + 8.58 + 6 + 4.2 = 48.53$

The total distance the ball has travelled after it hits the ground the 5th time is of 48.53m.

8 0

3 years ago