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maks197457 [2]
3 years ago
12

Mary made 8% more than Susan before Susan's 50 cent per hour raise to S22 per hour. How much does Mary make per hour?

Mathematics
1 answer:
lutik1710 [3]3 years ago
6 0

Answer:

Marry's income per hour= $23.22

Step-by-step explanation:

Susan's after raise of 50 cents income= $22 per hour

Susan's income before the raise= $(22-0.50)

= $21.5 per hour

Marry made 8% more than the Susan's income

Therefore, Marry's income= 21.5 +8% of 21.50

On the putting the values and calculating we get

Marry's income per hour= $23.22

Hope this helps and for any query please comment

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A random sample of 150recent donations at a certain
gtnhenbr [62]

Answer:

Null hypothesis:p\geq 0.4  

Alternative hypothesis:p < 0.4  

z=\frac{0.3 -0.4}{\sqrt{\frac{0.4(1-0.4)}{150}}}=-2.5  

p_v =2*P(Z  

If we compare the p value obtained and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that the true proportion is not significantly lower than 0.4 or 40% at 1% of significance.  

Step-by-step explanation:

1) Data given and notation  

n=150 represent the random sample taken

X=45 represent the people with type A blood

\hat p=\frac{45}{150}=0.3 estimated proportion of people with type A blood

p_o=0.4 is the value that we want to test

\alpha=0.01 represent the significance level

Confidence=99% or 0.99

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion of people type A blood is less than 0.4:  

Null hypothesis:p\geq 0.4  

Alternative hypothesis:p < 0.4  

When we conduct a proportion test we need to use the z statisitc, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.3 -0.4}{\sqrt{\frac{0.4(1-0.4)}{150}}}=-2.5  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.01. The next step would be calculate the p value for this test.  

Since is a bilateral test the p value would be:  

p_v =2*P(Z  

If we compare the p value obtained and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that the true proportion is not significantly lower than 0.4 or 40% at 1% of significance.  

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Step-by-step explanation:

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Step-by-step explanation:

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