we know the Inn is charging 155.82 and that's 100% plus 6%, namely 106% of an amout of say that is "x", being the 100%.
since we know that 155.82 is 106%, what is "x"?
![\begin{array}{ccll} amount&\%\\ \cline{1-2} 155.82&106\\ x&100 \end{array}\implies \cfrac{155.82}{x}=\cfrac{106}{100}\implies \cfrac{155.82}{x}=\cfrac{53}{50} \\\\\\ 7791=53x\implies \cfrac{7791}{53}=x\implies 147=x](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7Bccll%7D%20amount%26%5C%25%5C%5C%20%5Ccline%7B1-2%7D%20155.82%26106%5C%5C%20x%26100%20%5Cend%7Barray%7D%5Cimplies%20%5Ccfrac%7B155.82%7D%7Bx%7D%3D%5Ccfrac%7B106%7D%7B100%7D%5Cimplies%20%5Ccfrac%7B155.82%7D%7Bx%7D%3D%5Ccfrac%7B53%7D%7B50%7D%20%5C%5C%5C%5C%5C%5C%207791%3D53x%5Cimplies%20%5Ccfrac%7B7791%7D%7B53%7D%3Dx%5Cimplies%20147%3Dx)
Answer:
y>-2
Step-by-step explanation:
her mistake was she did -22-6= -28 but the correct solution is -22+6= -16
The possible ordered pairs whose product will be negative (less than zero) are,
![(x,-y) \: or \: (-x,y)](https://tex.z-dn.net/?f=%28x%2C-y%29%20%20%5C%3A%20or%20%5C%3A%20%20%28-x%2Cy%29%20)
That is all these products will give us,
![- xy](https://tex.z-dn.net/?f=%20-%20xy)
![-xy< 0](https://tex.z-dn.net/?f=%20-xy%3C%200)
The point must be in the second quadrant where x is negative and y is positive.
Or in the fourth quadrant, where y is negative and x is positive.
Answer:
1. 11/4
2. 19 1/4
Step-by-step explanation:
To change into an improper fraction:
((2 times 4)+3)/4
=11/4
To calculate total distance:
(11/4) times 7
=77/4
=19 1/4