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Otrada [13]
3 years ago
14

Which functions are the same as their inverse functions

Mathematics
1 answer:
9966 [12]3 years ago
4 0

Answer:

what functions?

Step-by-step explanation:

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Which answer is in slope-intercept form for the given equation?
zhuklara [117]

The slope-intercept form:

y = mx + b

m - slope

b - y-intercept

Answer:

B. y = 4/9x + 4

slope = 4/9, y-intercept = 4

D. y = -4/9x - 4

slope = -4/9, y-intercept = -4

6 0
3 years ago
Move the slider on the graph on the right to graph each function:
DedPeter [7]

Answer:

The domain is x\geq 7

The range is y\geq 1

Step-by-step explanation:

we have

y=\sqrt{x-7} +1

<em>Find the domain</em>

Remember that

The domain of a function is the set of all possible values of x

we know that the radicand of the function must be greater than or equal to zero

so

x-7\geq 0

solve for x

x\geq 7

therefore

The domain is x\geq 7

<em>Find the range</em>

Remember that

The range of a function is the complete set of all possible resulting values of y, after we have substituted the domain.

For x=7

The value of y is equal to

y=\sqrt{7-7} +1=1

so

The solution for y is the interval [1,∞)

therefore

The range is y\geq 1

6 0
2 years ago
Read 2 more answers
Solve the system of equations. <br><br> y=x+5 <br><br> y=-x+7
spin [16.1K]

Answer:

(1,6)

x = 1, y = 6

See attachment for the graph

Step-by-step explanation:

y=x+5  

y=-x+7

Using the elimination process

     y=x+5  

-     y=-x+7

----------------

     0=2x-2

     2=2x

      1=x

      x=1

Substitute x = 1

y = x + 5

y = 1 + 5

y = 6

4 0
3 years ago
Read 2 more answers
2 taps A and B can fill a swimming pool in 3 hours. If turned on alone, it takes tap A 5 hours less than tap B to fill the same
vazorg [7]

Answer:

Tap A will take 2 hours and tap B will take 6 hours to fill the tank when turned on alone.

Step-by-step explanation:

Let tap B fills the pool alone in the time = x hours

So in one hour part of pool will be filled = \frac{1}{x}

Another tap A when turned on, it takes time to fill the pool = x-5 hours

So in one hour part of the same pool filled = \frac{1}{x-5}

Now both the taps A and B are turned on then time taken to fill the pool = 3 hours.

Part of the pool filled in one hour by both the taps = \frac{1}{3}

Now we form an equation

Part of pool filled in one hour by tap A + Part of pool filled in one hour by tap B = Part of pool filled in one hour by both the taps when turned on

\frac{1}{(x-5)}+\frac{1}{x}=\frac{1}{3}

\frac{x-5+1}{x(x-5)}=\frac{1}{3}

\frac{x-4}{x(x-5)}=\frac{1}{3}

3(x - 4) = x(x - 5)

x² -5x = 3x - 12

x² - 8x + 12 = 0

x² - 6x - 2x + 12 = 0

x(x - 6) - 2(x - 6) = 0

(x -2)(x - 6) = 0

x = 2, 6 hours

We will take higher value of x as x = 6 hours for tap B.

Time taken by tap A = 6 - 4 = 2 hours.

Therefore, Tap A will take 2 hours and tap B will take 6 hours to fill the tank when turned on alone.

4 0
3 years ago
Show work please thanks
Tju [1.3M]
Be more specific on the first one
3 0
2 years ago
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