Answer:
Step-by-step explanation:
P=2l+2w
28=2l+2w
2l=2w-28
l = (2w-28)/2
l =2(w-14)/2
l = w-14
we know that
In the right triangle ABC
∠CAB=∠ABC=
so
we have
<u>using sines</u>
or
substitute the value of AB
or
<u>using cosines</u>
or
substitute the value of AB
or
therefore
<u>the answer is</u>
Let the weight of the heaviet package = X
Weight of the smallest package = X/2+(1/3*X/2)
= X/2+X/6
= 2X/3
Then
X+2X/3 = 100
(3X+2X)/3 = 100
5X/3 = 100
X = 300/5
= 60
Then the weight of the smallest package = 2X/3
= 2*60/3
= 40
So the weight of the smallest package is 40 Kg.
The answer is: D. -1/3 !! hope that helps