First term = T(1) is obtained by plugging n = 1 into the formula,
thus First term = 1^2 - 4 = 1 - 4
= 3 (answer)
72/5 or 14.4 hope this helped you
Answer:
formula: y-y1 = m(x-x1)
Step-by-step explanation:
General:
1. find 2 points directly on the line and apply the formula y2-y1 over x2-x1 this answer equals m
2. then add it into the formula y-y1 = m(x-x1) remember x and y are variables so only put numbers in y1 and x1
3. solve the problem
Example:
line 1:
1. y2-y1 over x2-x1 is 4-6 over 6-4 = -1
2. y-6 = -1(x-(-4) or y-6 = -1(x+4)
3. y-6 = -1x-4
4. y = -1x-2
3. the gradient equals: y = -1x-2
Hope this helps :) Let me know if you need a better example
i answer the questions that relate to the lessons i've learned
Answer:
The value of x is 8cm. The length of 3 sides are 8cm, 15cm and 17cm.
Step-by-step explanation:
Using Pythagoras' Theorem, a²+b² = c² :
Let a be x cm,
Let b be x+7 cm,
Let c be 2x+1 cm
x² + (x+7)² = (2x+1)²
x² + x² + 14x + 49 = 4x² + 4x + 1
2x² + 14x + 49 = 4x² + 4x + 1
Then, move all the variables to one side and solve it to find the value of x :
4x² + 4x + 1 - 2x² - 14x - 49 = 0
2x² - 10x - 48 = 0
2(x² - 5x - 24) = 0
x² - 5x - 24 = 0
(x-8)(x+3) = 0
x - 8 = 0
x = 8 cm
x + 3 = 0
x = -3 cm (rejected)
Substitute the x value into the length of a,b and c :
a = x
= 8 cm
b = x + 7
= 8 + 7
= 15 cm
c = 2x + 1
= 2(8) + 1
= 16 + 1
= 17 cm