Group 9 of the periodic table is comprised of cobalt (Co), Rhodium (Rh), Iridium (Ir), and one which is still chemically uncharacterized Meitnerium (Mt). These elements are all metals. These metals are termed Transition metals.
These metals are in the d-block because the last elements are in the d-orbitals.
Explanation:
Molecular formula
Molecular formula is used to represent exact no. of different atoms present in a molecule. For example, molecular formula of glucose is . That means one molecule of glucose has 6 molecules of C, 12 molecules of hydrogen and 6 molecules of oxyhen.
Structural formula
Graphic structure of a compound is represented by a structural formula. Bonding present between atoms are also shown. Structural formula of ethyl alcohol is shown in the attachment
Electron dot formula
Electron dot structure are used to represent possible structure of the compound along with bonding electrons and lone pair electrons. It is also known as Lewis dot structure. Electron dot structure of methane is shown in the attachment.
15.5% by mass is
equivalent 15.5 g urea in 100 g solution or 155 g urea in 1 kg solution. <span>
<span>we know that molality = moles solute / kg solvent
<span>moles solute = 155 g / 60 g/mol = 2.58 moles urea
</span></span></span>
Since there are 155 g
urea in 1000g solution, hence the solvent is 845 g or 0.845 kg
So:<span>
<span>molality = 2.58 / 0.845 = 3.06 m</span></span>
Temperature does not change, remains 264 K
<h3>Further explanation</h3>
Given
V₁= 1.2 L
P₁ = 1.8 atm
T₁ = 264
Required
The new temperature
Solution
The volume was doubled = 2V₁ = 2 x 1.2 = 2.4 L(V2)
The pressure was halved = 0.5P₁ = 0.5 x 1.8 = 0.9 atm(P2)
Combined gas law :
P₁V₁/T₁=P₂V₂/T₂
Input the value :
Answer:
Approximately 1.9 kilograms of this rock.
Explanation:
Relative atomic mass data from a modern periodic table:
To answer this question, start by finding the mass of Pb in each kilogram of this rock.
89% of the rock is . There will be 890 grams of in one kilogram of this rock.
Formula mass of :
.
How many moles of formula units in that 890 grams of ?
.
There's one mole of in each mole of . There are thus of in one kilogram of this rock.
What will be the mass of that of ?
.
In other words, the in 1 kilogram of this rock contains of lead .
How many kilograms of the rock will contain enough to provide 1.5 kilogram of ?
.