Answer:
True
Step-by-step explanation:
A six sigma level has a lower and upper specification limits between
and
. It means that the probability of finding no defects in a process is, considering 12 significant figures, for values symmetrically covered for standard deviations from the mean of a normal distribution:
![\\ p = F(\mu + 6\sigma) - F(\mu - 6\sigma) = 0.999999998027](https://tex.z-dn.net/?f=%20%5C%5C%20p%20%3D%20F%28%5Cmu%20%2B%206%5Csigma%29%20-%20F%28%5Cmu%20-%206%5Csigma%29%20%3D%200.999999998027%20)
For those with defects <em>operating at a 6 sigma level, </em>the probability is:
![\\ 1 - p = 1 - 0.999999998027 = 0.000000001973](https://tex.z-dn.net/?f=%20%5C%5C%201%20-%20p%20%3D%201%20-%200.999999998027%20%3D%200.000000001973%20)
Similarly, for finding <em>no defects</em> in a 5 sigma level, we have:
.
The probability of defects is:
![\\ 1 - p = 1 - 0.999999426697 = 0.000000573303](https://tex.z-dn.net/?f=%20%5C%5C%201%20-%20p%20%3D%201%20-%200.999999426697%20%3D%200.000000573303%20)
Well, the defects present in a six sigma level and a five sigma level are, respectively:
Then, comparing both fractions, we can confirm that a <em>6 sigma level is markedly different when it comes to the number of defects present:</em>
[1]
[2]
Comparing [1] and [2], a six sigma process has <em>2 defects per billion</em> opportunities, whereas a five sigma process has <em>600 defects per billion</em> opportunities.
A trig identity is <span>asinucosu=<span>a/2</span>sin(2u)</span>So you can write your equation as<span>y=sin(x)cos(x)=<span>1/2</span>sin(2x)</span>Use the crain rule here<span><span>y′</span>=<span>d/<span>dx</span></span><span>1/2</span>sin(2x)=<span>1/2</span>cos(2x)<span>d/<span>dx</span></span>2x=cos(2x)</span>The curve will have horizontal tangents when y' = 0.<span><span>y′</span>=0=cos(2x)</span>On the interval [-pi, pi], solution to that is<span><span>x=±<span>π4</span>,±<span><span>3π</span>4</span></span></span>
Answer:
b x h / 2
Step-by-step explanation:
The order does not matter, so we will be using combinations here. 52C1 is the first one since there is only one possibility. 16C1 is the second. You have to multiply these two, so 52 X 16 = 832.
{(-2, 6), (-5, -1), (3, 7), (-5, 0)}
Domain: The domain is all the x-values (-2, -5, 3, -5)
Range: The range is all the y-values (6, -1, 7, 0)
Function: It's not a function because of the x-value -5 is repeating.