Essentially what you're given is the following
![[total gallons for the specified time] = [gallons]*[days]\\](https://tex.z-dn.net/?f=%5Btotal%20gallons%20for%20the%20specified%20time%5D%20%3D%20%5Bgallons%5D%2A%5Bdays%5D%5C%5C)
The easiest way to approach this problem is to use the given information to find the amount of milk the family consumes over the course of a day.
So now that we know that the family drinks 
gallons of milk each day, we can multiply by the desired amount of days to discover how much milk the family drinks over that period of time.
So from this, we now know that the family drinks 
gallons of milk over the course of 4 days.
Answer:
3.37 times
Step-by-step explanation:
Probability of hitting and odd number= 3/5
Probability of hitting and odd number=2/5
Probability of hitting and odd number three times= (3/5)^3
Probability of hitting and odd number three times=(2/5)^3
Now
(3/5)^3 / (2/5)^3 = 3.37
Hence Probability of hitting an odd number three times is 3.37 times more than the probability of hitting an even number three times !
Answer:
I don't see a figure sorry
Answer:
-14+6x
Step-by-step explanation:
first we hade to add the number
