K^3-27 in difference of cubes

Mathematics

1 answer:

Luda [366]4 years ago

8 0

Answer:

(k - 3)(k^2 + 3k + 9)

Step-by-step explanation:

Base equation:

(k^3 - 3^3)

The first bracket will be a - b, second will be:

a^2 + ab + b^2

(k - 3)(k^2 + 3k + 9)

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Step-by-step explanation:

the two 135 degree angles indicate that the third angle (the one with the shaded region) is 90 degrees, which means that the shaded region is within 1/4 of the circle.

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[r^2(3.14)]/4 pi is substituted by 3.14, and the radius is 8.

50.24 is the area of 1/4 of the circle.

2. Next you'd have to find the area of the triangle formed by the shaded region, and subtract the triangle from the area of the 1/4 circle.

the triangle is an isoceles triangle with two sides each valuing at 8cm, so to find the area of the triangle you would multiply the two sides (or square them since they're the same number) and divide by two

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