Answer:
![\huge\boxed{A=3\sqrt{255}\ in^2\approx47.91\ in^2}](https://tex.z-dn.net/?f=%5Chuge%5Cboxed%7BA%3D3%5Csqrt%7B255%7D%5C%20in%5E2%5Capprox47.91%5C%20in%5E2%7D)
Step-by-step explanation:
We have two sides
![a=12in;\ b=14in](https://tex.z-dn.net/?f=a%3D12in%3B%5C%20b%3D14in)
and the preimeter
![P=34in](https://tex.z-dn.net/?f=P%3D34in)
We can calculate the length of the third side:
![c=P-a-b](https://tex.z-dn.net/?f=c%3DP-a-b)
substitute
![c=34-12-14=8\ (in)](https://tex.z-dn.net/?f=c%3D34-12-14%3D8%5C%20%28in%29)
Use the Heron's formula:
![A=\sqrt{p(p-a)(p-b)(p-c)](https://tex.z-dn.net/?f=A%3D%5Csqrt%7Bp%28p-a%29%28p-b%29%28p-c%29)
where
![p=\dfrac{P}{2}](https://tex.z-dn.net/?f=p%3D%5Cdfrac%7BP%7D%7B2%7D)
substitute:
![p=\dfrac{34}{2}=17\ (in)\\\\A=\sqrt{17(17-12)(17-14)(17-8)}=\sqrt{(17)(5)(3)(9)}\\\\=\sqrt{9}\cdot\sqrt{(17)(5)(3)}=3\sqrt{255}\ (in^2)\approx47.91\ (in^2)](https://tex.z-dn.net/?f=p%3D%5Cdfrac%7B34%7D%7B2%7D%3D17%5C%20%28in%29%5C%5C%5C%5CA%3D%5Csqrt%7B17%2817-12%29%2817-14%29%2817-8%29%7D%3D%5Csqrt%7B%2817%29%285%29%283%29%289%29%7D%5C%5C%5C%5C%3D%5Csqrt%7B9%7D%5Ccdot%5Csqrt%7B%2817%29%285%29%283%29%7D%3D3%5Csqrt%7B255%7D%5C%20%28in%5E2%29%5Capprox47.91%5C%20%28in%5E2%29)
1 times 4 =4 then 5i
Equation:
5i + 4
Answer:
Step-by-step explanation:
Shaped area perimeter=50(3)+50
÷2+50(2)
÷4
=150+50![\pi](https://tex.z-dn.net/?f=%5Cpi)
=307.1 cm(correct to nearest tenth)
Desmos is a graphing calculator just put in your equation and it will show you the graph for it