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marta [7]
3 years ago
10

How to do this in math

Mathematics
1 answer:
Mandarinka [93]3 years ago
6 0

Answer:

How to do what in math?

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Find all zeros x^3+2x^2+4x+21
dlinn [17]

Answer:

see explanation

Step-by-step explanation:

note when x = - 3

(- 3)³ + 2(- 3)² + 4(- 3) + 21 = - 27 + 18 - 12 + 21 = 0

hence x = - 3 is a zero and (x + 3) is a factor and dividing gives

\frac{x^3+2x^2+4x+21}{x+3} = (x + 3)(x² - x + 7)

For zeros equate to zero

(x + 3)(x² - x + 7) = 0

equate each factor to zero and solve for x

x + 3 = 0 ⇒ x = - 3

x² - x + 7 = 0 ← solve using quadratic formula

x = (1 ± \sqrt{1-28} ) / 2 = (1 ± 3i\sqrt{3} ) / 2

x = \frac{1}{2} ± \frac{3i\sqrt{3} }{2}

zeros are x = - 3, x = \frac{1}{2} ±\frac{3i\sqrt{3} }{2}


5 0
3 years ago
Make d the subject of the formula h= d/3 + 2
Leni [432]

Answer:

d= 3h-6

Step-by-step explanation:

h= d/3+2

h-2= d/3

d= 3(h-2)= 3h-6

5 0
3 years ago
Read 2 more answers
A=?<br><br> b=?<br><br> C =?<br><br> Can someone tell me the answer please
beks73 [17]

Answer:

Below.

Step-by-step explanation:

a = 37 degrees ( vertical angle to 37 )

c = 180 - 37 = 143 degrees (adjacent angles add up to 180).

b = 180 - 37 - 109 = 34 degrees   (angles in a triangle sum to 180 degrees).

5 0
2 years ago
Read 2 more answers
Consider the points.
miskamm [114]

Answer:

6 units

Step-by-step explanation:

Use the distance formula, \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}.

Plug the x and y values from the given points into the distance formula:

\sqrt{([-4]-2)^{2}+(5-5)^{2}}.

Solve the square root:

\sqrt{36} = \sqrt{6^{2}} = 6

3 0
3 years ago
The value of (1-w) (1 -w^2), where w is the cube root of a complex number is
NeX [460]

Answer:(1-w) (1-w*2)

=1-w*2-w+w*3

=1-w-w*2+1

=1-1+1

=1

Step-by-step explanation:

at first we should multiply them with each other

then, put the value of w*3 i.e. w*3=1

then, put the value of -w-w*2 i.e. 1

then, the final answer is 1.

3 0
2 years ago
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