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mart [117]
3 years ago
7

Question 11 Find the value of y. X+ 13 45° No links please! Thanks for the help!​

Mathematics
2 answers:
9966 [12]3 years ago
7 0

Answer:

First option: 13 \sqrt{2}

Step-by-step explanation:

cosθ =  \frac{adj}{hyp}

cos45° =  \frac{13}{y}

Multiply both sides by y:

y(cos45°) = 13

y ( \frac{ \sqrt{2} }{2} ) = 13

y = 13 \div  \frac{ \sqrt{2} }{2}

y = 13 \times  \frac{2}{ \sqrt{2} }

y =  \frac{26}{ \sqrt{2} } ( \frac{ \sqrt{2} }{ \sqrt{2} } )

y =  \frac{26 \sqrt{2} }{2}

y = 13 \sqrt{2}

PilotLPTM [1.2K]3 years ago
4 0

Option A

{\pink{y = 13 \sqrt{2}}}

<h2 /><h2 /><h2><u>Solution :- </u></h2>

\sf{cosθ=  \frac{ B}{C} }

\dashrightarrow \sf \: {cos45° = \frac{13}{y} }

<u>Multiply both sides by y:</u>

\sf \ \: y(cos45°) = 13y(cos45°)=13

\sf \: y ( \frac{ \sqrt{2} }{2} ) = 13

\implies \sf \: y = 13 \div \frac{ \sqrt{2} }{2}

\sf \implies \: y = 13 \times \frac{2}{ \sqrt{2} }

\implies \sf \: y = \frac{26}{ \sqrt{2} } ( \frac{ \sqrt{2} }{ \sqrt{2} } )

\implies \sf y = \frac{26 \sqrt{2} }{2}

\sf \boxed {\pink{y = 13 \sqrt{2}}}

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The system of equations when been placed in a matrix yields

\left[\begin{array}{ccc}650&-1\\120&1\end{array}\right]\left[\begin{array}{ccc}x\\y\end{array}\right]  =\left[\begin{array}{ccc}-175\\25080\end{array}\right]

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Find out more on equation at: brainly.com/question/2972832

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