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inn [45]
3 years ago
9

If cos(Θ) = -2 9 , and 90° < θ < 180°, what is the value of tan(θ)?

Mathematics
1 answer:
frosja888 [35]3 years ago
7 0
We know that

if  <span>90° < θ < 180°
</span>then
θ--------------> belong to the second quadrant
so
tan θ is negative

sin² θ + cos² θ=1----------> sin² θ=1-cos² θ----->sin² θ=1-(-2/9)²
sin² θ=1-(4/81)------> 77/81----------> sin θ=√(77/81)------> √77/9
sin θ=(√77)/9

tan θ=sin θ/cos θ------> [(√77)/9]/[-2/9]-------> -√77/2

the answer is the option
<span>A) -77sqroot/2</span>
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