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3 years ago

Classify the following triangle. Check all that apply.

Mathematics

1 answer:

Olenka [21]3 years ago

8 0

The triangle is scalene and obtuse

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What would be m minus 4 in an algebraic expression

12345 [234]

It's just m minus 4
m - 4

6 0

3 years ago

I have to find the slope and the y-intersect from these graphs. It would mean alot if someone could help with at least one of th

Sati [7]

Answer:

Alright bear with me, this is gonna be a long one.

The Y INTERCEPT

So the y-intercept is going to be where the line intersects the Y-AXIS. The y-axis is the vertical part of the graph with the numbers on it.

So, for the first one, the line goes through the origin which means that that the y intercept is going to be (0,0)

The next one, the line intersects the y-axis at (0,1)

Here's a tip: the y-intercept will always have 0 as it's x coordinate.

The Slope

Alright, the slope of a vertical line can be found using an equation. Most typically people will describe the slope as RISE/RUN meaning how many units you move up "rise" and how many units you move horizontally "run" to touch the line. Of course, it's easier when you can identify points.

So to make this a little bit easier to understand, I will show you how to use the equation to find the slope.

$\frac{y2-y1}{x2-x1}$

So for this equation, what you need is two coordinates. So for the first graph, I'm going to use the points (0,0) and (1,3)

$\frac{3-0}{1-0}$

So we make the three y2 because it's the second y coordinate and the y1 would be 0. Same applies to the x coordinates but use the x values.

the slope for the first graph would be 3/1

FOR THE SECOND GRAPH

$\frac{y2-y1}{x2-x1}$

Here's our equation now pick two points. I'll be using (-5,4) and (0,1)

$\frac{1-4}{0-(-5)}$

Don't forget that a negative-a negative = positive

which will leave you with

$\frac{-3}{5}$

since it can't be simplified any further, your slope is -3/5.

I hope I was able to help you understand this a bit better :)

3 0

4 years ago

A girl starts to walk to her school, which is 20 miles away, at 6:50 and at a rate of 3 miles per hour. After a while, her dad p

Alexeev081 [22]

The girl walked a distance of $\boxed{{\mathbf{5 miles}}}$ in her way.

Further explanation:

The time can be calculated as,

${\text{ time}}=\frac{{{\text{distance}}}}{{{\text{speed}}}}$

Given:

It is given that a girl stands 20 miles away from the school at $6:50{\text{ am}}$ and she started walking at the rate of $3{\text{ mi/hr}}$ and then after some time her dad pick up and he drives at the rate of $30{\text{ mi/hr}}$ . They reach the school at $9:00{\text{ am}}$ .

Step by step explanation:

Step 1:

Consider $x$ as the distance she walked in her way.

The speed of the girl when she walked is $3{\text{ mi/hr}}$ .

Now use the formula of time to obtain the walk time.

$\begin{gathered}{\text{ walktime}}=\frac{{{\text{distance walked}}}}{{{\text{walking speed}}}}\hfill\\{\text{ walktime}}=\frac{x}{3}\hfill\\\end{gathered}$

Since the total distance is $20{\text{ miles}}$ .

Then consider $20-x$ as the distance driven by the car.

The driving speed is $30{\text{ mi/hr}}$ .

Now use the formula of time to obtain the drive time.

$\begin{gathered}{\text{drive time}}=\frac{{{\text{distance travelled by car }}}}{{{\text{ speed of car}}}}\hfill\\{\text{drive time}}=\frac{{20-x}}{{30}} \hfill\\\end{gathered}$

Step 2:

Now we calculate the total time took by girl to reach the school.

$9:00-6:50={\text{2 hrs 10 min}}$

Now convert the timing into hours as,

$\begin{aligned}2{\text{ hours 10 minutes}}&=2+\frac{{10}}{{60}}\\&=2\frac{1}{6}\\&=\frac{{13}}{6}{\text{ hrs}}\\\end{aligned}$

Step 3:

Total time is the sum of drive time and walk time.

The total time can be expressed as,

$\frac{x}{3}+\frac{{20-x}}{{30}}=\frac{{13}}{6}$

Now solve the above equation by cross multiply method.

$\begin{aligned}\frac{x}{3}+\frac{{20-x}}{{30}}&=\frac{{13}}{6}\hfill\\\frac{{10x+20-x}}{{30}}&=\frac{{13}}{6}\hfill\\\frac{{9x+20}}{{30}}&=\frac{{13}}{6}\hfill\\6\left({9x+20}\right)&=13\left({30}\right)\hfill\\\end{aligned}$

Now simplify the further equation.

$\begin{aligned}6\left({9x+20}\right)&=13\left({30}\right)\hfill\\54x+120&=390\hfill\\54x&=390-120\hfill\\54x&=270\hfill\\\end{aligned}$

Simplify the further equation.

$\begin{aligned}54x&=270\hfill\\x&=\frac{{270}}{{54}}\hfill\\x&=\frac{{45}}{9}\hfill\\x&=5\hfill\\\end{gathered}$

Therefore, the girl walked 5 miles.

Learn more:

Learn more about the distance between the points brainly.com/question/6278187

Learn more about the equivalent fraction brainly.com/question/952259

Learn more about midpoint of the segment brainly.com/question/3269852

Answer details:

Grade: High school

Subject: Mathematics

Chapter: Speed, distance and time

Keywords: girl, distance, drive, walk, drive time, dad, speed, travelled, formula, cross multiply, fraction, number, multiply, addition, subtraction, equation, school

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4 years ago

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Grace is comparing cell phone plans. A prepaid phone plan costs $0.20 per minute and has no monthly fee. A contracted phone plan

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The answer would be A. or the first one.

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4 years ago

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