A rectangular playground has a perimeter of 180 feet. If the width of the playground is 24 feet less than the length, what is th
e width, in feet, of the playground?
A. 27
B. 33
C. 51
D. 57
1 answer:
P = 2(L + W)
P = 180
W = L - 24
now we sub
180 = 2(L + L - 24)
180 = 2(2L - 24)
180 = 4L - 48
180 + 48 = 4L
228 = 4L
228/4 = L
57 = L
W = L - 24
W = 57 - 24
W = 33
so ur length (L) = 57 ft and ur width (W) = 33 ft
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- tan (<Q)=11/8
- m(<Q)=tan^-1(11/8)=53.96°
- tan(<P)=8/11
- m(<P)=tan^-1(8/11)=36.02°
- QP=Square root of (8)^2+(11)^2=square root 185
- the answer of the second question is 53°
Answer
a) 3/4 x = 9
x = 
x = 12
b) 10+ 3x = 5x
2 x = 10
x = 5
c) a + x = b
x = b - a
d) c x = d
x = 
e) 
x < 2( m + g)
f) q + 5 x = 7 x - r
q + r = 2 x
V= pi r2 h/3
V= pi (6)2 (8/3)
V= pi (36) (2.6)
V= pi (93.6)
V= 293.904
Hope this helps!
Answer:
bueh
Step-by-step explanation:
Answer:
1) 2b + 6
2) 8w - 12
3) 2b + 6 + 6x + 20
4) 9w^2 + 27 + 8 - 27
5) Sorry.
Step-by-step explanation:
