Potencial Energy=hma
Where
Potencial Energy =E= 54.9J
h=?
m=8kg
a=9.8m/s^2
You need to know that 1 J=1(kgm^2)/s^2
Isolate h=E/(ma)
h=(54.9)/(8*9.8)
Answer:
3 m/s
Explanation:
We'll begin by calculating the change in displacement of the jogger. This can be obtained as follow:
Initial displacement (d₁) = 4 m
Final displacement (d₂) = 16 m
Change in displacement (Δd) =?
Δd = d₂ – d₁
Δd = 16 – 4
Δd = 12 m
Finally, we shall determine the determine the average velocity. This can be obtained as follow:
Change in displacement (Δd) = 12 m
Time (t) = 4 s
Velocity (v) =?
v = Δd / t
v = 12 / 4
v = 3 m/s
Thus, the average velocity of the jogger is 3 m/s
Answer:
t' = 458.26 μs
Explanation:
given,
distance traveled by the cosmic ray = 60 Km
time = 500 μs
time taken for the journey according to cosmic ray = ?
now,
v = 1.2 x 10⁸ m/s
according to time dilation formula
t' = 500 x 0.9165
t' = 458.26 μs
