Answer:
m= 2[kg]
Explanation:
Linear momentum can be calculated as the product of mass by Velocity.
where:
P = linear momentum = 3 [kg*m/s]
v = velocity = 1.5 [m/s]
m = mass [kg]
If two protons and two neutrons are removed from the nucleus of an oxygen atom, a nucleus of which element remains?
1 answer:
You might be interested in
Let's start by using the mirror equation:
where f=10 cm is the focal lenght of the mirror, d=38 cm is the distance of the object from the mirror, while q is the distance of the image from the mirror.
For the sign convention, f is taken as positive for a concave mirror. Therefore, we can solve the equation for q:
from which we find q=13.6 cm.
The fact that q is positive means that the image is real, so it is on the same side of the object, with respect to the mirror.
Then we can also find the size of the image with respect to the original object. The magnification is given by
The negative sign means that the image is inverted, and the size of the image is 0.36 times the size of the object.
where f=10 cm is the focal lenght of the mirror, d=38 cm is the distance of the object from the mirror, while q is the distance of the image from the mirror.
For the sign convention, f is taken as positive for a concave mirror. Therefore, we can solve the equation for q:
from which we find q=13.6 cm.
The fact that q is positive means that the image is real, so it is on the same side of the object, with respect to the mirror.
Then we can also find the size of the image with respect to the original object. The magnification is given by
The negative sign means that the image is inverted, and the size of the image is 0.36 times the size of the object.
Answer:
The work done on the gas = 2PV
Explanation:
In this question, we need to apply the basic gas laws to determine the word done.
For this question, we need to draw a PV diagram (a pressure-volume diagram), which I have made and attached in the attachment. So please refer to that attachment. I will be using this diagram to solve for the work done on the gas.
So, Please refer to the attachment number 1. where x -axis is of volume and y-axis is of pressure.
As we know that, the work done on the gas is equal to the area under the curve.
W = Area of the triangle
W = 0.5 x ( base) x ( height)
W = 0.5 x (BC) x (AC)
W = 0.5 x (3V-V) x (3P-P)
W = 2PV
Hence, the work done on the gas = 2PV
