Such that |x-a|<\varepsilon and $x-b|<\varepsilon. can $a$ be countable? can $a$ be uncountable?

An observer at the top of a 532 foot cliff measures the angle of depression from the top of the cliff to a point on the ground t

Over [174]

Answer:

Distance from the base of the cliff to the point on the ground = 7608 feet

Step-by-step explanation:

Given: Height of the cliff is 532 feet, angle of depression from the top of the cliff to a point on the ground is equal to 4 degrees.

To find: distance from the base of the cliff to the point on the ground

Solution:

In ΔABC,

$\angle ACB=4^{\circ}$ (Alternate interior angles)

For any angle $\theta$ , $\tan \theta =$ side opposite to angle/side adjacent to angle

$\tan C=\frac{AB}{BC}$

Put $AB=532\,,\,\angle C=4^{\circ}$

$\tan 4^{\circ}=\frac{532}{BC}\\\\BC=\frac{532}{\tan 4^{\circ}}\\\\=7607.95\\\\\approx 7608\,\,feet$

Distance from the base of the cliff to the point on the ground = 7608 feet

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5 0

3 years ago

The areas of two similar triangles are 75m2 and 300m2. The length of one of the sides of the second triangles is 9m. What is the

Ymorist [56]

Answer:

4.5 m

Step-by-step explanation:

The area of two similar triangles are 75 m2 and 300 m2. This gives you the scale factor of the triangles:

$\dfrac{A_{small}}{A_{large}}=k^2\Rightarrow k^2 =\dfrac{75}{300}=\dfrac{3}{12}=\dfrac{1}{4}\Rightarrow k=\dfrac{1}{2}.$

Then you can find the length of the corresponding side:

$\dfrac{side_{small}}{side_{large}}=k\Rightarrow =\dfrac{side_{small}}{9}=\dfrac{1}{2},\ side_{small}=\dfrac{9}{2}=4.5\ m.$

4 0

3 years ago

Can someone help me please

ANTONII [103]

B.) 85

They are alternate interior angles so they are the same degree.

3 0

2 years ago

The relative frequency table shows a survey on the support for candidate x in an upcoming national election. In this survey, 75

maxonik [38]

Answer:

D.

Step-by-step explanation:

a) no, because 50% of people who support candidate x are from California, but only 62.5% of all people in the study are from California.

b) yes, because 50% of people who support candidate x are from California, but only 62.5% of all people in the study are from California.

c) no, because 62.5% of people who support candidate x are from California, but only 50% of all people in the study are from California.

d) yes, because 62.5% of people who support candidate x are from California, but only 50% of all people in the study are from California.

The answer is D.

8 0

3 years ago

Read 2 more answers

What is the product?

aliya0001 [1]

Answer:

20s³ + 50s² + 32s + 6

Step-by-step explanation:

( 4s + 2 ) ( 5s² + 10s + 3)

use the distribution property:

20s³ + 40s² + 12s + 10s² + 20s + 6

combine like terms:

20s³ + 50s² + 32s + 6

therefore

the expand value = 20s³ + 50s² + 32s + 6

3 0

3 years ago