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3 years ago

15

What percentage of the distance covered by an Olympic triathlon do athletes cycle if they swim 3%, run for 20% and cycle the rem

ainder?

2 answers:

Igoryamba3 years ago

7 0

cycling=100%-22%=78%

Please mark me as brainiest

alexgriva [62]3 years ago

4 0

Cycling = 100% -3% -20%
Cycling = 100% -23%
Cycling = 77%

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PLEASE HELP ME EVERYONE HAS GOTTEN THIS WRONG ITS GONNA SUBMIT IN 15 MIN PLS HELP THANK YOU

LiRa [457]

Answer:

x=4.8

This here you use Pythagorean Theorem.

Step-by-step explanation:

a^2+b^2=c^2

The longest side is c. And the two legs are a and b.

So it'd be 11^2+x^2=12^2

121+x^2=144

Subtract 121 from both sides.

x^2=23

Then take the √ of x^2 and 23

So √x^2=√23

x=4.8

Hope this helps

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3 years ago

Ten times the number, x, is one-half the sum of the number and three

Mazyrski [523]

10x=1/2x+3

I think it's right, but not 100% sure

7 0

3 years ago

Read 2 more answers

What is the midpoint of the segment (1, -1) (4, -6)

Sophie [7]

When looking for the midpoint of a segment defined by two end points, the average of both coordinates are taken. Averaging the 2 x-coordinates give the new x-coordinate, and the same applies for the y-coordinate. This is shown below:

Midpoint = ( (1 + 4)/2 , (-1 + -6)/2 )
Midpoint = (2.5 , -3.5)

6 0

3 years ago

Suppose the inside bottom of a box is painted with three colors: one-third of the bottom area is blue, one-sixth is red, and one

miss Akunina [59]

Answer:

The probability that the pebble will NOT land on color blue is 0.67.

Step-by-step explanation:

We attribute the box area as the probability of the events.

So the probability of landing in the Red Area is 1/6, the probability of landing in the Blue Area is 1/3 and the probability of landing in the Yellow Area is 1/2.

P(Red)= $\frac{1}{6}$

P(Yellow)= $\frac{1}{2}$

P(Blue)= $\frac{1}{3}$

The probability of landing in NOT Blue area is given by:

P(Not Blue)=1-P(Blue)= $1-\frac{1}{3}=\frac{2}{3} =0.67$

8 0

3 years ago

2. You are given the hyperbolic relation modeled by xy = -2. Do the following: a) Rewrite the relation such that the dependent v

N76 [4]

$▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪$

The given equation is :

$xy = - 2$

1. The relationship such that dependent variable (y) is isolated is :

$y = \dfrac{ - 2}{x}$

2. The table accompanying this equation :

x = -4 and y = 0.5

x = -1 and y = 2

x = - 0.5 and y = 4

x = 0 and y = undefined

x = 0.5 and y = -4

x = 1 and y = -2

x = 4 and y = -0.5

3. graph of the given equation is in attachment ~

4 0

3 years ago