Question

A line includes the points (6,10) and (1,0) What is its equation in slope-intercept form?

Answer 1

Answer:

The slope-intercept is $y = 2x -2$ .

Step-by-step explanation:

-First, you need to find the slope by using the slope formula:

$m =\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

-Second, use both points (6, 10) and (1, 0) for the formula:

$m =\frac{0-10}{1-6}$

-Third, you solve:

$m =\frac{0-10}{1-6}$

$m = 2$

-Fourth, after you found the slope, you need to use the Point-slope form equation:

$y - y_{1} = m (x -x_{1})$  (where $m$ represents the slope, and $(x_{1},y_{1})$ represents the first coordinate or the first point).

-Fifth, use the slope 2 and the first point (6, 10) for the Point-slope form equation:

$y - 10= 2 (x -6)$

-Sixth, you solve the equation to get the slope-intercept form:

$y - 10= 2 (x -6)$

$y -10 = 2x -12$

$y -10 +10 = 2x -12 +10$

$y = 2x -2$

So, therefore, the slope-intercept is $y = 2x -2$ .