Please help me with this thank you
2 answers:
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The complete question in the attached figure
we know that
<span>The measure of the external angle is the semidifference of the arcs that it covers.
so
</span><span>m∠BED =(1/2)*[mAC-mBD]-------> solve for mBD
mBD=mAC-2</span>m∠BED
mBD=80-2*25--------> mBD=30°
the answer is
mBD=30°
we know that
<span>The measure of the external angle is the semidifference of the arcs that it covers.
so
</span><span>m∠BED =(1/2)*[mAC-mBD]-------> solve for mBD
mBD=mAC-2</span>m∠BED
mBD=80-2*25--------> mBD=30°
the answer is
mBD=30°
Answer:
(a) x = 30°
(b) mRS = 30°
mST = 120°
mTU = 120°
mUR = 90°
Step-by-step explanation:
(a) In the picture attached, the diagram is shown.
Given that m arc RS = x, from the ratios:
m arc ST = 4x
m arc TU = 4x
m arc UR = 3x
The addition of the four arcs must be equal to 360°, then:
x + 4x + 4x + 3x = 360°
12x = 360°
x = 360°/12 = 30°
(b) m arc RS = x = 30°
m arc ST = 4x = 4*30° = 120°
m arc TU = 4x = 4*30° = 120°
m arc UR = 3x = 3*30° = 90°
Step-by-step explanation:
Given the information:
- 1st square: 12 square units
- 2nd square: DOUBLE that of the first square = 2*12 = 24 square units
From that, we can determine the length of the side in each square:
1/
<=> x = 2
2/
<=> a = 2
Please have a look at the attached photo.
Hope it will find you well.
