Question

Factor completely 20x^2 y - 4xy Someone put steps for me when solving, thank you

Answer 1

20x^2y - 4xy

First, we look at what terms are common between each term.

There is a 4 present in the last term, and 4 is a factor of 20, so that is one factor.

Each term also includes at least one x, and one y, so x and y are also factors.

We can factor a 4, an x, and a y out of this.

4xy(5x - 1) is the fully factored form of this binomial.

Answer 2

20x^2 y - 4xy
y(20x^2 - 4x)
4y(5x^2 - x)
4xy(5x - 1)