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3 years ago

Factor completely 20x^2 y - 4xy Someone put steps for me when solving, thank you

Mathematics

2 answers:

zavuch27 [327]3 years ago

8 0

20x^2y - 4xy

First, we look at what terms are common between each term.

There is a 4 present in the last term, and 4 is a factor of 20, so that is one factor.

Each term also includes at least one x, and one y, so x and y are also factors.

We can factor a 4, an x, and a y out of this.

<h3><u>4xy(5x - 1) is the fully factored form of this binomial. </u></h3>

krok68 [10]3 years ago

3 0

20x^2 y - 4xy
y(20x^2 - 4x)
4y(5x^2 - x)
4xy(5x - 1)

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A stockbroker earns a base salary of 40000 dollar plus 5%of the total value of the stocks,mutual funds , and other investments t

lisabon 2012 [21]

Well his salary is $40,000 dollars.

$72,750 - $40,000 = $32,750

This means that 5% of the value of investments he had sold was equal to $32,750.

$\frac { 1 }{ 20 } \times I=32750\\ \\ 20\times \frac { 1 }{ 20 } \times I=20\times 32750\\ \\ \therefore \quad I=655000$

The stockbroker sold $655,000 worth of investments.

7 0

4 years ago

Which binomial is a factor of 9x2 – 64? 3x – 8 9x – 32 3x 32 9x 8

aalyn [17]

The binomial factor of the equation $\rm 9x^2 -64$ is 3x-8.

<h3>What is a binomial factor?</h3>

The algebraic expression which contains only two terms is called binomial. It is a two-term polynomial. Also, it is called a sum or difference between two or more monomials.

Factoring binomials means breaking down a binomial expression into its simplest form.

Binomials are algebraic expressions with two terms.

The given binomial is;

$\rm 9x^2 -64$

The binomial is determined in the following steps given below.

$\rm =9x^2 -64\\\\= (3)^2x^2-8^2\\\\= (3x)^2-8^2\\\\= (3x-8)(3x+8)$

Hence, the binomial factor of the equation $\rm 9x^2 -64$ is 3x-8.

To know more about the Binomial factor click the link given below.

brainly.com/question/1493247

3 0

3 years ago

How do i factor 2x^2+11x+5

ira [324]

For simple integer factors as this one has, you want to find two values for the quadratic in the form ax^2+bx+c. Let the two values be j and k. These two values must satisfy two conditions.

jk=ac=10 and j+k=b=11, so j and k must be 1 and 10.

Now replace bx with jx and kx...

2x^2+x+10x+5 now factor 1st and 2nd pair of terms.

x(2x+1)+5(2x+1)

(x+5)(2x+1)

7 0

3 years ago

Read 2 more answers

Ok, now i need help from 1-5, 20 points

ratelena [41]

1 = 8

2=3+8

3=12

4=9

8 that's it bra

5 0

4 years ago

PLEASE HELP! ill give brainliest

kolbaska11 [484]

Answer:

look at the sbse below

Step-by-step explanation:

∠DEC ≅ ∠DCE, ∠ACB ≅ ∠GEF,

∠B ≅ ∠F, DF ≅ BD

∠ACB ≅ ∠GEF, ∠B ≅ ∠F, DF ≅ BD, ΔABC ≅ ΔGFE.

i hope this helps you :) it took me a long time

3 0

3 years ago