So Jj earns a flat rate of 180 per week and an extra 15 per tablet he has sold
so what we need to do is subtract his flat rate(180) from his total(315)
315
-180
____
135 So now we know how much money Jj has earned from selling tablets. But we still need to create an equation and find out how many he has sold.
So we know he get $15 per tablet so 135÷15=9
now we know he has sold 9 tablets
Bu what is our Equation?
well, what were the steps?
TP = total pay
FR= Flat rate
C= Computer profit
PPC= price per computer
#C = number of computers
#C = TP-FR=C C÷PPC=#C
can we simplify this further?
#C = C÷PPC
lets do this:
#C= x
C= y
PPC= z
So: (X = Y÷Z)
Answer:As 1,000 multiplied by 1 equals 1,000. So, 1000 is thousand times bigger than 1. For instance, 100 is 10 times bigger than 10.
Step-by-step explanation: Brandon .w.
2200 miles done by getting rid of the exponents and multiplying
For the first question break it down to 2 rectangles and add the areas
14 * 4
and (12-4) * 8 = 8* 8
secon q:-
The other rectangle which has area of 72 is the third choice. Its perimmeter = 2(24) + 2(8) = 64
Answer: 1800
Step-by-step explanation:
Given : A certain system has two components.
Number of different models of the first component = 6
Number of different models of the second component = 10
A salesman must select 2 of the first component and 3 of the second to take on a sales call , so we use combinations ( ∵ order of selection not matters)
The number of different sets of components can the salesman take = 
![\dfrac{6!}{2!(6-2)!}\times\dfrac{10!}{3!(10-3)!}\ \ [\because\ ^nC_r=\dfrac{n!}{r!(n-r)!}]](https://tex.z-dn.net/?f=%5Cdfrac%7B6%21%7D%7B2%21%286-2%29%21%7D%5Ctimes%5Cdfrac%7B10%21%7D%7B3%21%2810-3%29%21%7D%5C%20%5C%20%5B%5Cbecause%5C%20%5EnC_r%3D%5Cdfrac%7Bn%21%7D%7Br%21%28n-r%29%21%7D%5D)
Hence, the number of different sets of components can the salesman take = 1800
