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True [87]
3 years ago
8

Which statement below correctly depicts the expected value of a fair game?

Mathematics
2 answers:
nydimaria [60]3 years ago
6 0

Answer:

Step-by-step explanation:

First of all it is important to know about the fair game.  A game is said to be fair if it has equal chances of winning for both the parties.

In Statistical terms, this can be said as expected value =0

If E(X) = 1 where X is from the player, then organizer of the game would have more chances of losing.

Similarly if E(X)>0where X is from the player, then organizer of the game would have more chances of losing.

Also if E(X)>1, where X is from the player, then organizer of the game would have more chances of losing.

Hence a fair game is one where

E(X) =0

Mnenie [13.5K]3 years ago
3 0
E(x)=0 will be your answer

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The solution to the equation is p = 1/3 and q = undefined

<h3>How to solve the equation?</h3>

The equation is given as:

p^2 - 2qp + 1/q = (p - 1/3)

The best way to solve the above equation is by the use of a graphing calculator i.e. graphically

However, it can be solved algebraically too (to some extent)

Recall that the equation is given as:

p^2 - 2qp + 1/q = (p - 1/3)

Split the equation

So, we have

p^2 - 2qp + 1/q = 0

p - 1/3 = 0

Solve for p in p - 1/3 = 0

p = 1/3

Substitute p = 1/3  in p^2 - 2qp + 1/q = 0

So, we have

(1/3)^2 - 2q(1/3) + 1/q = 0

This gives

1/9 - 2/3q + 1/q = 0

This gives

2/3q + 1/q = -1/9

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2/3q^2 + 1 = -1/9q

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6q^2 + q + 9 = 0

Using the graphing calculator, we have

q = undefined

Hence. the solution to the equation is p = 1/3 and q = undefined

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brainly.com/question/13763238

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