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Marrrta [24]
3 years ago
14

Please help!

Mathematics
2 answers:
Snezhnost [94]3 years ago
4 0

-9i(-9i+4)+3(8+8i)


Use the distributive property to remove the parenthesis:


-9i * -9i = 81i^2

-9i x 4 = -36i

3x8 = 24

3x8i = 24i

Now you have 81i^2 - 36i + 24 + 24i


i^2 = -1


Now you have 81 x -1 - 36i + 24 + 24i


-81 +24 = -57

-36i +24i = -12i


Final answer = -57 - 12i


The answer is D.

Igoryamba3 years ago
3 0

Answer:

D

Step-by-step explanation:

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Ivan

Answer:

2x + x +90= 180 We will add 2x + x=3x We get 3x + 90 =180 Now we subtract 3x = 180–90 ... x=30, for confirmation put value of x =30in equation and verify. LHS=RHS. Thats it. 68 views.

8 0
3 years ago
First answer gets Brainlyist
Naddik [55]
Answer: 4th graph

Explanation:

3x _> 3
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We can write x like this:

1 <_ x < 6

Meaning that x is bigger or equal to 1 but less than 6
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How many thirds are in 4/5?
meriva

Answer:

5/12

Step-by-step explanation:

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6 0
2 years ago
The volume of a boys' basketball is 434 cubic inches. Dan would like to get a ball
Nataly_w [17]

Answer:

The correct answer is A. 9.4 inches.

Step-by-step explanation:

Given that the volume of a boys' basketball is 434 cubic inches, and Dan would like to get a ball with half the volume for his son, to determine what is the diameter of the ball that Dan will buy for his son, the following calculation has to be done, knowing that the volume of a sphere is four thirds multiplied by pi multiplied by the radius cubed:

4/3 x 3.14 x X ^ 3 = 434

4.186 x X ^ 3 = 434

X ^ 3 = 434 / 4.186

X = 3√ 103.662

X = 4.7

In turn, since the radius of a sphere is equal to half its diameter, the diameter of the basketball is 9.4 inches (4.7 x 2).

4 0
3 years ago
A circle has the equation 2x²+12x+2y²−16y−150=0.
KonstantinChe [14]

Answer: B. The coordinates of the center are (-3,4), and the length of the radius is 10 units.

Step-by-step explanation:

The equation of a circle in the center-radius form is:

(x-h)^{2} +(y-k)^{2}=r^{2} (1)

Where (h,k) are the coordinates of the center and r is the radius.

Now, we are given the equation of this circle as follows:

2x^{2}+12x+2y^{2}-16y-150=0 (2)

And we have to write it in the format of equation (1). So, let's begin by applying common factor 2 in the left side of the equation:

2(x^{2}+6x+y^{2}-8y-75)=0 (3)

Rearranging the equation:

x^{2}+6x+y^{2}-8y=75 (4)

(x^{2}+6x)+(y^{2}-8y)=75 (5)

Now we have to complete the square in both parenthesis, in order to have a perfect square trinomial in the form of (a\pm b)^{2}=a^{2}\pm+2ab+b^{2}:

<u>For the first parenthesis:</u>

x^{2}+6x+b^{2}

We can rewrite this as:

x^{2}+2(3)x+b^{2}

Hence in this case b=3 and b^{2}=9:

x^{2}+2(3)x+3^{2}=x^{2}+6x+9=(x+3)^{2}

<u>For the second parenthesis:</u>

y^{2}-8y+b^{2}

We can rewrite this as:

y^{2}-2(4)y+b^{2}

Hence in this case b=-3 and b^{2}=9:

y^{2}-2(4)y+4^{2}=y^{2}-8y+16=(y-4)^{2}

Then, equation (5) is rewritten as follows:

(x^{2}+6x+9)+(y^{2}-8y+16)=75+9+16 (6)

<u>Note we are adding 9 and 16 in both sides of the equation in order to keep the equality.</u>

Rearranging:

(x-3)^{2}+(y-4)^{2}=100 (7)

At this point we have the circle equation in the center radius form (x-h)^{2} +(y-k)^{2}=r^{2}

Hence:

h=-3

k=4

r=\sqrt{100}=10

8 0
3 years ago
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