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Phantasy [73]
3 years ago
11

Please help me fast because I’m being timed!!

Chemistry
1 answer:
Sergio [31]3 years ago
5 0

Answer:

i cant see

Explanation:

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What is cell wall? Where is it found?​
Lady_Fox [76]

Answer:

A cell wall is a fairly rigid layer surrounding a cell located outside of the plasma membrane that provides additional support and protection. They are found in bacteria, archaea, fungi, plants, and algae. Animals and most other protists have cell membranes without surrounding cell walls.

Explanation:

3 0
3 years ago
Read 2 more answers
A mixture of water and acetone at 756 mm boils at 70.0°C. The vapor pressure of acetone is
Tatiana [17]

Given :

A mixture of water and acetone at 756 mm boils at 70.0°C.

The vapor pressure of acetone is  1.54 atm at 70.0°C, while the vapor pressure of water is 0.312 atm at the same temperature.

To Find :

The percentage composition of the mixture.

Solution :

By Raoult's law :

P=x_{acetone}P^o_{acetone}+x_{water}P^o_{water}\\\\x_{acetone}1.58+x_{water}0.312=\dfrac{756}{760}=0.995\ atm\\\\1.58x_a+0.312x_w=0.995......( 1 )

Also , x_a+x_b=1      ......( 2 )

Solving equation 1 and 2 , we get :

x_a=0.54\ and \ x_w=0.46 .

Mass of acetone ,

m_a=x_a\times MM_a\\\\m_a=0.54\times 58\\\\m_a=31.32\ g

Mass of water ,

m_w=x_w\times MM_w\\\\m_w=0.46\times 18\\\\m_a=8.28\ g

\%water =\dfrac{8.28}{8.28+31.32}\times 100\\\\\%water =20.9\%\\\\\%acetone =79.1\%

Hence , this is the required solution.

6 0
3 years ago
A buffer can be prepared by mixing two solutions. Determine if each of the following mixtures will result in a buffer solution o
cestrela7 [59]

Answer:

1) A. "Yes, it will result in a buffer solution."

2) A. "Yes, it will result in a buffer solution."

3) A. "No, it will not result in a buffer solution."

4) B. No, it will not result in a buffer solution."

5) B. No, it will not result in a buffer solution.

Explanation:

A buffer system is formed by two components:

  • A weak acid and its conjugate base.
  • A weak base and its conjugate acid.

<em>1) Mixing 100.0 mL of 0.1 M HF with 100.0 mL of 0.05 M mol KF. </em>A. "Yes, it will result in a buffer solution."

HF is a weak acid and F⁻ is its conjugate base.

<em>2) Mixing 100.0 mL of 0.1 M NH₃ with 100.0 mL of 0.1 M NH₄Br.</em> A. "Yes, it will result in a buffer solution."

NH₃ is a weak base and NH₄⁺ is its conjugate acid.

<em>3) Mixing 100.0 mL of 0.1 M HCN with 100.0 mL of 0.05 M KOH.</em> A. "No, it will not result in a buffer solution."

It does not have the components of a buffer system.

<em>4) Mixing 100.0 mL of 0.1 M HCl with 100.0 mL of 0.1 M KCl.</em> B. No, it will not result in a buffer solution."

It does not have the components of a buffer system (HCl is a strong acid).

<em>5) Mixing 100.0 mL of 0.1 M HCN with 100.0 mL of 0.1 M KOH.</em> B. No, it will not result in a buffer solution.

It does not have the components of a buffer system.

3 0
3 years ago
The isotope of hydrogen that has two neutrons is called A. hydrogen. B. deuterium. C. tritium. D. dihydrogen.
lutik1710 [3]

Answer:

C.Tritium

Explanation:

Isotopes are forms of an element with different mass number but same atomic number. Mass number is the sum of the number of protons and neutrons in the nucleus of an atom, while atomic number is the number of protons.

Mass number = protons +neutrons.

Atomic number = protons only

We can say that mass number = atomic number + number of neutrons.

The number of neutrons is what differentiates the isotopes of an element.

For hydrogen element, it has three isotopes namely; protium, deuterium and tritium which have 0,1 and 2 neutrons respectively. Thus the answer is C

7 0
3 years ago
Solid potassium fluoride decomposes into fluorine gas and solid potassium .
dsp73

Answer:

                2 KF ₍s₎    →    F₂ ₍g₎  +  2 K ₍s₎

Explanation:

                    Chemical Formula of Potassium Fluoride  =  KF

                    Chemical Formula of Fluorine Gas  =  F₂

                    Chemical Formula of Solid Potassium  =  K

Step 1: Write the unbalance chemical equation,

                                             KF    →    F₂  +  K

Step 2: Balance Fluorine Atoms;

As there is one fluorine atom on left hand side and two fluorine atoms on right hand site therefore, to balance them multiply KF on left hand side by 2 i.e.

                                            2 KF    →    F₂  +  K

Step 3: Balance Potassium Atoms;

As there are two potassium atoms on left hand side and one potassium atom on right hand site therefore, to balance them multiply K on right hand side by 2 i.e.

                                             2 KF    →    F₂  +  2 K

Step 4: Assign Physical states as,

                                      2 KF ₍s₎    →    F₂ ₍g₎  +  2 K ₍s₎

8 0
3 years ago
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