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Aleksandr [31]
4 years ago
5

A 50.0-ml volume of 0.15 m hbr is titrated with 0.25 m koh. calculate the ph after the addition of 11.0 ml of koh. express your

answer numerically.
Chemistry
1 answer:
gayaneshka [121]4 years ago
4 0
<span>pH = 1.1 First, determine how many moles of each reactant was used Moles HBr = 0.0500 l * 0.15 mol/l = 0.0075 mol Moles KOH = 0.0110 l * 0.25 mol/l = 0.00275 mol Now determine how much acid (HBr) is left over after the rest of it is neutralized by the KOH. A simple matter of subtraction. 0.0075 - 0.00275 = 0.00475 mol Now determine the molarity of HBr. That would be moles per volume, so 0.00475 mol / (0.0500 l + 0.0110 l) = 0.00475 mol / 0.061 l = 0.077868852 mol/l = 0.077868852 m Now since HBr is a strong acid, it will completely dissociate into H+ and Br- ions. So the molarity of the H+ ions will be the same as the molarity of HBr. And the definition of pH is pH = - log(H+) So the log of 0.077868852 is -1.108636228 And the negation of that is 1.108636228 So the pH is 1.1 to 2 significant figures since that's the precision of the data we were given.</span>
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Nitric acid (HNO3) is a strong acid that is completely ionized in aqueous solutions of concentrations ranging from 1% to 10% (1.
Alborosie

<u>Given:</u>

Concentration of HNO3 = 7.50 M

% dissociation of HNO3 = 33%

<u>To determine:</u>

The Ka of HNO3

<u>Explanation:</u>

Based on the given data

[H+] = [NO3-] = 33%[HNO3] = 0.33*7.50 = 2.48 M

The dissociation equilibrium is-

            HNO3   ↔    H+      +      NO3-

I            7.50               0                 0

C          -2.48          +2.48              +2.48

E            5.02            2.48              2.48

Ka = [H+][NO3-]/HNO3 = (2.48)²/5.02 = 1.23

Ans: Ka for HNO3 = 1.23

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3 years ago
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klasskru [66]

Heat transfer is the phenomenon that occurs when the two objects are in the vicinity of each other and by increasing the area of their contact. Thus, option B is correct.

<h3>What is heat transfer?</h3>

Heat transfer is a process that flows the heat from one system to another, and is because of the difference in the temperature of the two objects that are part of the system.

The methods like conduction, convection, and radiation transfer the heat from the surface area to the other object. The heat gets transferred from the area of high to the low temperature.

Therefore, option B. by increasing the surface area the heat transfer increases.

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