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PolarNik [594]
3 years ago
11

What could reduce the heat island effect around cities?

Chemistry
1 answer:
melamori03 [73]3 years ago
5 0

Answer: (D.) Planting Roof gardens

Explanation: I'm really hoping you get this right but the reason of my answer is because Trees, green roofs, and vegetation can help reduce urban heat island effects by shading building surfaces, deflecting radiation from the sun, and releasing moisture into the atmosphere.

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The atoms of some radioactive isotopes, or radioisotopes, are used in scientific studies. They are called _______.
lys-0071 [83]

Radioactive Isotopes


Hope this helps

7 0
4 years ago
Where does the largest percent of water exist on Earth?
Ivanshal [37]

Answer:

97% of earth's water is in the ocean. The rest could be found underground, in glaciers and ice, and in rivers and lakes

3 0
3 years ago
If sock type A is pulled first, sock type B second, and sock type C third, the fourth sock type must match one of A, B, or C.
alexandr1967 [171]

Answer:

a

Explanation:

sock type a is first then other sock types

5 0
3 years ago
How many moles of oxygen will occupy a volume of 2.5 liters at 1.2 atm
Citrus2011 [14]

<u>We are given:</u><u>_______________________________________________</u>

Volume of Gas (V) = 2.5L

Pressure (P) = 1.2 atm

Temperature (T) = 25°C  OR 25+273 = 298 K

Universal Gravitational Constant (R) = 0.0821

<u>Solving for number of moles:</u><u>___________________________________</u>

From the Ideal Gas Equation,

PV = nRT

(1.2)(2.5) = n(0.0821)(298)           [plugging the given values]

n = [(1.2)(2.5)] / [0.0821*298]

n = 300 / [298*8.21]

n = 0.12 moles

Hence, there are 0.12 moles of Oxygen in 2.5L of 1.2 atm gas when the temperature is 25°C

7 0
3 years ago
For H 3 PO 4 and H 3 BO 3 , does the subscript " of hydrogen in these two formulas seem to result in additional ions in solution
Kay [80]

Answer:

See Explanation

Explanation:

Let us consider the ionization of these compounds;

H3PO4 ⇔3H^+ + PO4^3-

H3BO3  ⇔3H^+ + BO3^3-

The next to consider is the type of electrolyte the both solution are; the both solutions are weak electrolytes and weak electrolytes do not ionize to a large extent.

The implication of this is that, not so much number of ions is added to the solution due to the poor ionization of these weak electrolytes. Hence, in spite of the subscript of 3, the conductivity of the solution does not significantly improve for the reason stated here quite unlike when strong electrolytes are used.

6 0
3 years ago
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