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Tcecarenko [31]
3 years ago
12

What are the smallest units of an ionic bond?

Chemistry
1 answer:
lapo4ka [179]3 years ago
7 0
The smallest units is a formula unit
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a 75.0 liter canister contains 15.82 moles of argon at a pressure of 546.8 kilopascals. What is the temperature of the canister?
abruzzese [7]

Pressure of argon = 546.8 kPa

Conversion factor: 1 atm = 101.325 kPa

Pressure of argon = 546.8 kPa x 1 atm/101.325 kPa = 5.4 atm

Moles of argon = 15.82

Volume of argon = 75.0 L

According to Ideal gas law,

PV = nRT

where P is the pressure, V is the volume , n is the number of moles, R is the universal gas constant, and T is the temperature

T = PV/nR = (5.4 atm x 75.0 L) / (15.82 x 0.0821 L.atm.mol⁻¹K⁻¹)

T = 311.82 K

Hence the temperature of the canister is 311.82 K.

4 0
3 years ago
If 40.0 g of molten iron(II) oxide reacts with 10.0 g of mag-nesium, what is the mass of iron produced
vagabundo [1.1K]

Answer:

m_{Fe}=23.0gFe

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

FeO+Mg\rightarrow Fe+MgO

Thus, for the given masses of reactants we should compute the limiting reactant for which we first compute the available moles of iron (II) oxide:

n_{FeO}=40.0gFeO*\frac{1molFeO}{72gFeO} =0.556molFeO

Next, we compute the consumed moles of iron (II) oxide by the 10.0 g of magnesium, considering their 1:1 molar ratio in the chemical reaction:

n_{FeO}^{consumed}=10.0Mg*\frac{1molMg}{24.3gMg}*\frac{1molFeO}{1molMg}=0.412molFeO

Therefore, we can notice there is less consumed iron (II) oxide than available for which it is in excess whereas magnesium is the limiting reactant. In such a way, the produced mass of iron turns out:

m_{Fe}=0.412molFeO*\frac{1molFe}{1molFeO}*\frac{56gFe}{1molFe}\\  \\m_{Fe}=23.0gFe

Regards.

8 0
4 years ago
A hydrated salt is a solid that includes water molecules within its crystal structure. A student heated a 12.10-gram sample of a
sveticcg [70]

Answer : The percent by mass of water the salt contain is, 55.3 %

Explanation : Given,

Mass of hydrated salt = 12.10 g

Mass of salt = 5.41 g

First we have to calculate the mass of water.

Mass of water = Mass of hydrate salt - Mass of salt

Mass of water = 12.10 g - 5.41 g

Mass of water = 6.69 g

Now we have to calculate the percent by mass of water the salt contain.

\text{Percent by mass of water}=\frac{\text{Mass of water}}{\text{Mass of hydrate salt}}\times 100

Now put all the given values in this expression, we get:

\text{Percent by mass of water}=\frac{6.69g}{12.10g}\times 100

\text{Percent by mass of water}=55.3\%

Therefore, the percent by mass of water the salt contain is, 55.3 %

5 0
3 years ago
Name the phase change in each of these events: (c) Wet clothes dry on a summer day
8090 [49]

The phase change occurs during evaporation. On a hot day, wet clothing is drying. A liquid becomes a gas when it evaporations.

During the process of evaporation, a liquid transforms into a gaseous phase that is not saturated with the evaporating substance. The term "vaporization of a liquid" refers to this process. Clothes start to dry as water vapor escapes from the fabric's surface.

<h3>What is evaporation?</h3>

A liquid turns into a gas through the process of evaporation. Raindrops that "vanish" on a hot day or damp clothing that dries in the sun are good examples of the phenomena. In these instances, the liquid water is evaporating into a gas known as water vapor rather than really dissipating. Global evaporation takes place.

Learn more about evaporation: brainly.com/question/5019199

#SPJ4

5 0
2 years ago
How many grams of C are required to react with 97.1 g of Fe2O3?
sashaice [31]

Answer:

21.9 g C

Explanation:

Fe₂O₃  +  3 C  ⇒  2 Fe  +  3 CO

This is your chemical equation.  

To find the grams of C required, first convert grams of Fe₂O₃ to moles using the molar mass (159.69 g/mol).  

(97.1 g)/(159.69 g/mol) = 0.608 mol Fe₂O₃

Then, use the mole ratio between Fe₂O₃ and C to convert moles of Fe₂O₃ to moles of C.  You can find the mole ratio by looking at the chemical equation.

(0.608 mol Fe₂O₃) × (3 mol Fe₂O₃/1 mol Fe₂O₃) = 1.824 mol C

You can then convert moles of C to grams using the molar mass (12.01 g/mol).

(1.824 mol) × (12.01 g/mol) = 21.9 g

5 0
3 years ago
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