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marin [14]
3 years ago
6

What volume (in mL) of a 0.113 M NaCl solution contains 0.087 mol NaCl?

Chemistry
1 answer:
Helen [10]3 years ago
5 0
Hello I a m s o m o n e I n t h e w o r l d
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3 years ago
A student is instructed to make 1 L of a 2.0 M solution of CaCl2 using dry salt. How should he do this?
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<span>The student should follow following steps to make 1 L of </span>2.0 M CaCl₂.<span>
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1. First he should calculate the number of moles of 2.0 M CaCl</span></span>₂ in 1 L solution.<span>

</span>Molarity of the solution = 2.0 M<span>
Volume of solution which should be prepared = 1 L

Molarity = number of moles / volume of the solution

Hence, number of moles in 1 L = 2 mol

2. Find out the mass of dry CaCl</span>₂ in 2 moles.<span>

moles = mass / molar mass

Moles of CaCl₂ = 2 mol</span><span>
Molar mass of CaCl₂ = </span><span>110.98 g/mol

Hence, mass of CaCl</span>₂ = 2 mol x <span>110.98 g/mol
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3. Weigh the mass accurately 

4. Then take a cleaned and dry1 L volumetric flask and place a funnel top of it. Then carefully add the salt into the volumetric flask and finally wash the funnel and watch glass with de-ionized water. That water also should be added into the volumetric flask.

5. Then add some de-ionized water into the volumetric flask and swirl well until all salt are dissolved.

<span>6. Then top up to mark of the volumetric flask carefully. 
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7. As the final step prepared solution should be labelled.
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