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Dimas [21]
3 years ago
12

The base of a rectangular prism is a square. The height of a prism is half the length of one edge of the base. The volume of rec

tangular prism is 13.5 cubic units. What are the dimensions of a prism?
Mathematics
1 answer:
SSSSS [86.1K]3 years ago
3 0

Answer:

3 × 3 × 1.5

Step-by-step explanation:

Volume = base area × height

13.5 = s² × ½s

½s³ = 13.5

s³ = 27

s = 3

½s = 1.5

Dimensions:

3 × 3 × 1.5

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Lelu [443]

Answer:

25\pi Or 78.5 units³

Step-by-step explanation:

1/3πr²h

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7 0
2 years ago
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Find c if m A = 70.6°, b = 10.4 in
nata0808 [166]

Answer:

its 7.8

Step-by-step explanation:

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2 years ago
Help.........................<br><br>​
garri49 [273]
<h3>Answer: Choice A</h3>

x^2\left(\sqrt[4]{x^2}\right)

=====================================================

Explanation:

The fourth root of x is the same as x^(1/4)

I.e,

\sqrt[4]{x} = x^{1/4}

The same applies to x^10 as well

\sqrt[4]{x^{10}} = \left(x^{10}\right)^{1/4}

Multiply the exponents 10 and 1/4 to get 10/4

\sqrt[4]{x^{10}} = \left(x^{10}\right)^{1/4} = x^{10*1/4} = x^{10/4}

\sqrt[4]{x^{10}} = x^{10/4}

-----------------------

If we have an expression in the form x^(m/n), with m > n, then we can simplify it into an equivalent form as shown below

x^{m/n} = x^a\sqrt[n]{x^b}

The 'a' and 'b' are found through dividing m/n

m/n = a remainder b

'a' is the quotient, b is the remainder

-----------------------

The general formula can easily be confusing, so let's replace m and n with the proper numbers. In this case, m = 10 and n = 4

m/n = 10/4 = 2 remainder 2

We have a = 2 and b = 2

So

x^{m/n} = x^a\sqrt[n]{x^b}

turns into

x^{10/4} = x^2\sqrt[4]{x^2}

which means

\sqrt[4]{x^{10}} = {x^2} \sqrt[4]{x^2}

7 0
3 years ago
in a game using two dice, a person wins if the outcome is a prime number. Find the probability of winning.
AlexFokin [52]

Answer:

45% I think because prime numbers are 5/ the 11 possible numbers when rolling two die

7 0
3 years ago
A pan is heated to 393°F, then removed from the heat and allowed to cool in a kitchen where the room temperature is a constant 6
deff fn [24]

Answer:

The approximate temperature of the pan after it has been away from the heat for 9 minutes is 275.59°F.

Step-by-step explanation:

The formula for D, the difference in temperature between the pan and the room after t minutes is:

D = 324\cdot e^{-0.05t}

Compute the approximate difference in temperature between the pan and the room after 9 minutes as follows:

D = 324\cdot e^{-0.05t}

    =324\times e^{-0.05\times 9}\\\\=206.59

Then the approximate temperature of the pan after it has been away from the heat for 9 minutes is:

D = P - R

206.59 = P - 69

P = 206.59 + 69

P = 275.59°F

Thus, the approximate temperature of the pan after it has been away from the heat for 9 minutes is 275.59°F.

6 0
2 years ago
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