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3 years ago

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The base of a rectangular prism is a square. The height of a prism is half the length of one edge of the base. The volume of rec

tangular prism is 13.5 cubic units. What are the dimensions of a prism?

1 answer:

SSSSS [86.1K]3 years ago

3 0

Answer:

3 × 3 × 1.5

Step-by-step explanation:

Volume = base area × height

13.5 = s² × ½s

½s³ = 13.5

s³ = 27

s = 3

½s = 1.5

Dimensions:

3 × 3 × 1.5

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Read 2 more answers

The graph 4x^2-4x-1 is shown. Use the grpah to find the estimates for the solutions of 4x^2-4x-1=0 and 4x^2 - 4x-1=2

Darina [25.2K]

Answer:

a) The estimates for the solutions of $4\cdot x^{2}-4\cdot x -1 = 0$ are $x_{1}\approx -0.25$ and $x_{2} \approx 1.25$ .

b) The estimates for the solutions of $4\cdot x^{2}-4\cdot x -1 = 2$ are $x_{1}\approx -0.5$ and $x_{2} \approx 1.5$

Step-by-step explanation:

From image we get a graphical representation of the second-order polynomial $y = 4\cdot x^{2}-4\cdot x -1$ , where $x$ is related to the horizontal axis of the Cartesian plane, whereas $y$ is related to the vertical axis of this plane. Now we proceed to estimate the solutions for each case:

a) $4\cdot x^{2}-4\cdot x -1 = 0$

There are two approximate solutions according to the graph, which are marked by red circles in the image attached below:

$x_{1}\approx -0.25$ , $x_{2} \approx 1.25$

b) $4\cdot x^{2}-4\cdot x -1 = 2$

There are two approximate solutions according to the graph, which are marked by red circles in the image attached below:

$x_{1}\approx -0.5$ , $x_{2} \approx 1.5$

5 0

3 years ago

Express in simplest a+bi form: Square root of 1b + Square root of -1b

Nimfa-mama [501]

Express in simplest a+bi form: Square root of 1b + Square root of -1b

$\sqrt{1b} + \sqrt{-1b}$

Lets simplify $\sqrt{-b}$

We know $\sqrt{-1} = i$

$\sqrt{-b} =i\sqrt{b)$

We cannot simplify $\sqrt{1b}$

$\sqrt{1b} + \sqrt{-1b}$

$\sqrt{1b} + i\sqrt{b}$

So a + ib form is $\sqrt{1b} + i\sqrt{b}$

5 0

3 years ago

The annual rainfall (in inches) in a certain region is normally distributed with = 40 and = 4. What is the probability that star

sdas [7]

Answer:

0.93970

Step-by-step explanation:

Solution:-

- Denote a random variable "X" The annual rainfall (in inches) in a certain region . The random variable follows a normal distribution with parameters mean ( μ ) and standard deviation ( σ ) as follows:

X ~ Norm ( μ , σ^2 )

X ~ Norm ( 40 , 4^2 ).

- The probability that it rains more than 50 inches in that certain region is defined by:

P ( X > 50 )

- We will standardize our test value and compute the Z-score:

P ( Z > ( x - μ ) / σ )

Where, x : The test value

P ( Z > ( 50 - 40 ) / 4 )

P ( Z > 2.5 )

- Then use the Z-standardize tables for the following probability:

P ( Z < 2.5 ) = 0.0062

Therefore, P ( X > 50 ) = 0.0062

- The probability that it rains in a certain region above 50 inches annually. is defined by:

q = 0.0062 ,

- The probability that it rains in a certain region rains below 50 inches annually. is defined by:

1 - q = 0.9938

n = 10 years ..... Sample of n years taken

- The random variable "Y" follows binomial distribution for the number of years t it takes to rain over 50 inches.

Y ~ Bin ( 0.9938 , 0.0062 )

- The probability that it takes t = 10 years for it to rain:

= 10C10* ( 0.9938 )^10 * ( 0.0062 )^0

= ( 0.9938 )^10

= 0.93970

3 0

3 years ago