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rewona [7]
3 years ago
11

What is the approixation of squared root 48

Mathematics
1 answer:
rosijanka [135]3 years ago
8 0
7 because the square root of 49 is 7, so its approximately 7.
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Determine the midpoint between the two points x(4,-6) and y(-2,8)
ikadub [295]

Answer:

p(a, b) = (1, 1)

Step-by-step explanation:

Midpoint formula is

p(a, b)=(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} ) ---------------(1)

Here

(x_1, y_1) = (4, -6) \ \ \ and \ \ \ (x_2, y_2) = (-2, 8)

Substituting values in equation (1)

p(a, b)=(\frac{4 - 2}{2}, \frac{-6 + 8}{2} )

p(a, b) = (1, 1)

6 0
3 years ago
Robert is a high school basketball player. In a particular game, he made some three point shots and some free throws (worth one
Oksanka [162]

Answer:

let t = number of three-point shots

let f = number of free throw shots

Step-by-step explanation:

t + f = 9      (he made a total of 9 shots altogether)

3t + 1f = 23   (number of shots multiplied by their point value)

substitution method:   t = 9 - f

                                    3(9 - f) + f = 23

                                     27 - 3f + f = 23

                                      -2f = -4

                                         f = 2

find 't':                               t + 2 = 9

                                         t = 7

                                         

8 0
3 years ago
Please help veryyy urgent due today!!!!!!
Musya8 [376]
42 is the answer....
4 0
3 years ago
Equivalent expression of 7 square root 5
Vika [28.1K]

Answer:19

Step-by-step explanation:

Subtract then add

4 0
3 years ago
3(s-5)/4 -3 = 4s- (s-3)/2<br>pls answer fast​
Jobisdone [24]

Answer:

s =  \frac{9± \sqrt{ - 39} }{4}

Step-by-step explanation:

\frac{3(s - 5)}{4 - 3}  =  \frac{4s \times (s - 3)}{2}

➡️ \frac{3(s - 5)}{1}  = 2s \times (s - 3)

➡️ 3s - 15 = 2 {s}^{2}  - 6s

➡️ 3s - 15  -  2 {s}^{2}  + 6s = 0

➡️ 9s - 15 - 2 {s}^{2}  = 0

➡️ - 2 {s}^{2}  + 9s - 15 = 0

➡️ 2 {s}^{2}  - 9s + 15 = 0

➡️ s =  \frac{ - ( - 9)± \sqrt{( - 9 {)}^{2}  - 4 \times 2 \times 15} }{2 \times 2}

➡️ s =  \frac{9± \sqrt{81 - 120} }{4}

➡️ s =  \frac{9± \sqrt{ - 39} }{4}

➡️ s∉ℝ

5 0
3 years ago
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