Answer:
Step-by-step explanation:
by idetity : (a - b)²= a² +b² -2ab
for : (x² - 5)² you have a = x² and b = 5
(x² - 5)²= (x²)²+5² - 2(5)(x²)
(x² - 5)²= x^4+25 -10x²
Answer:
The Proof with Figure, Statement and Reasons is given below.
Step-by-step explanation:
Given:
∠DAF ≅ ∠EBF,
DF ≅ FE
Prove:
Δ ADF ≅ Δ BFE
Proof:
Statements Reasons
a. ∠DAF ≅ ∠EBF ...........................Given
<u>48. ∠DFA ≅ ∠EFB </u>..........................Vertical Angles are congruent
DF ≅ FE ..........................<u>.49. Given</u>
50.<u> Δ ADF ≅ Δ BFE </u>.......................<u>..By Angle-Angle-Side test</u>
Answer: true
Step-by-step explanation: f(x) is a function because each x value (left oval) has one y value (right oval)!
3/12 = 1/4
If simplified then second option
The probability of choosing a number that is not a multiple of 2 is P = 0.44
<h3 /><h3>How to find the probability?</h3>
We need to count the number of options for each digit.
- For the first digit, we have 8 options {1, 2, 3, 4, 5, 6, 7, 8}
- For the second digit, we have 9 options {0 ,1, 2, 3, 4, 5, 6, 7, 8}
- For the third digit, we have 9 options {0 ,1, 2, 3, 4, 5, 6, 7, 8}.
The total number of combinations is the product between the numbers of options:
C = 8*9*9 = 648
If we want our number to not be a multiple of 2 then it must end in a odd digit, the combinations that meet that condition are:
- For the first digit, we have 8 options {1, 2, 3, 4, 5, 6, 7, 8}
- For the second digit, we have 9 options {0 ,1, 2, 3, 4, 5, 6, 7, 8}
- For the third digit, we have 4 options {1, 3, 5, 7}.
C = 8*9*4 = 288
Then the probability of selecting a 3 digit number that is not a multiple of 2 is:
P = 288/648 = 0.44
If you want to learn more about probability, you can read:
brainly.com/question/251701
