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Art [367]
2 years ago
5

Four notebooks 4.40. how many notebooks can you buy for 6.60.

Mathematics
1 answer:
denis23 [38]2 years ago
6 0
We know we have $4.40 for 4. Divide 4.40 by 4, you get 1.10. So it's $1.10 per notebook. Therefore, divide 6.60 by 1.10. You get 6, so you can get six notebooks with $6.60.
Hope this helps!
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Find the perimeter of square of having 6cm length<br>​
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Answer:

24 cm

Step-by-step explanation:

Perimeter = (sx2) + (sx2)

= (6x2) + (6x2)

= 12 + 12

= 24 cm

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The difference of twice a number and five is three. Find the number.
zmey [24]

2x - 5 = 3

2x = 3 + 5 = 8

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For what value of x is PQ || BC?<br> A 5<br> B. 6<br> C. 7<br> D. 8
Dahasolnce [82]

Answer:

C. 7

Step-by-step explanation:

In\: \triangle ABC\\\overline{PQ} \parallel \overline {BC}.. (given) \\

Therefore, by Basic Proportionality theorem:

\frac{AP}{PB} = \frac{AQ}{QC} \\\\\therefore \frac{x}{x+7} = \frac{x-3}{x+1} \\\\ \therefore \:  \frac{x - x - 7}{x + 7}  =  \frac{x - 3 - x - 1}{x + 1}  \\ (by \: dividendo) \\  \\  \frac{ - 7}{x + 7}  =  \frac{ - 4}{x + 1}  \\  \\  \frac{7}{x + 7}  =  \frac{4}{x + 1}  \\  \\ 7x + 7 = 4x + 28 \\  \\ 7x - 4x = 28 - 7 \\  \\ 3x = 21 \\  \\ x =  \frac{21}{3}  \\  \\ \huge \red{ \boxed{ x = 7}}

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3 years ago
Which type of engineer would be most likely to test the operating system of a new tablet?
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b hoped i helped :) your welcome btw

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Estimate the minimum number of subintervals to approximate the value of Integral from negative 3 to 3 (2 x squared plus 9 )dx wi
vichka [17]

Answer:

The value of n for (a) n=425. (b) n=0.

Step-by-step explanation:

Given integration is,

\int_{-3}^{3}f(x)=\int_{-3}^{3}(2x^2+9)dx

(a) For Trapezoidal Rule : Composite error is,

E_T=-\frac{(b-a)^3}{12n^2}f''(x_m)

Where, f''(x_m)=greatest value of |f''(x)|= |4|=4, a=-3, b=3. Therefore to find the minimum number of subinterval,

|E_T|\leq | \frac{(b-a)^3}{12n^2}f''(x)||

\leq \frac{4(-3-3)^3}{12n^2}

=\frac{72}{n^2}

According to the question, we must choose n such that,

\frac{72}{n^2}

\implies n>424.2640686

So we can take n=425.

(b) For Simpson 1/3 rule : Composite error is,

E_S=-\frac{(b-a)^5}{180n^4}f^{(iv)}(x_m)

where, f^{(x_m)}=\textit{greatest value of} |f^{(iv)}(x)|

In this problem f^{(iv)}(x)=0, so that,

|E_S|\leq 0

that is there exist no error. So n=0.

6 0
3 years ago
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