Question

Two groups of students were asked how far they lived from their school. The table below shows the distances in miles

Answer 1

Group A (distance in miles) 1 1.5 3.03 3.2 2.8 1.5 1.8 2.5 2.2
Group B (distance in miles) 2 2.5 3.23 1.3 1.8 2.4 3 1.5 1.8

Group A mean = (1 + 1.5 + 3.03 + 3.2 + 2.8 + 1.5 + 1.8 + 2.5 + 2.2)/9 = 19.53/9 = 2.17
Group B mean = (2 + 2.5 + 3.23 + 1.3 + 1.8 + 2.4 + 3 + 1.5 + 1.8)/9 = 19.53/9 = 2.17

Therefore, the mean is equal for Group A and Group B.

Answer 2

Answer:

The correct option is A) It is equal for Group A and Group B.

Step-by-step explanation:

Consider the provided information.

Group A (distance in miles) 1, 1.5, 3.03, 3.2, 2.8, 1.5, 1.8, 2.5, 2.2

Find the mean by using the formula: $mean=\frac{\text{Sum of terms}}{\text{Number of terms}}$

$mean=\frac{1+1.5+3.03+3.2+2.8+1.5+1.8+2.5+2.2}{9}$

$mean=\frac{19.53}{9}$

$mean=2.17$

Group B (distance in miles) 2, 2.5, 3.23, 1.3, 1.8, 2.4, 3, 1.5, 1.8

$mean=\frac{2+2.5+3.23+1.3+1.8+2.4+3+1.5+1.8}{9}$

$mean=\frac{19.53}{9}$

$mean=2.17$

Hence, the mean of both group are same.

Therefore, the correct option is A) It is equal for Group A and Group B.