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MrRissso [65]
3 years ago
12

What is 2/5 times 5/16

Mathematics
1 answer:
melomori [17]3 years ago
7 0

Answer:

1/8

Step-by-step explanation:

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The length of a rectangular garden is 5 times its width.
Delvig [45]

Answer:

  • 10 m and 50 m

Step-by-step explanation:

<h3>Given</h3>
  • l = 5w
  • A = 500 m²
<h3>To find</h3>
  • Length and width
<h3>Solution</h3>

Area formula

  • A = lw
  • A= 5w*w= 5w²
  • 5w² = 500
  • w²= 100
  • w = √100
  • w = 10 m

Then

  • l = 5w = 5*10 m = 50 m

3 0
3 years ago
A hardware dealer has 168kg of nails, if one nail weighs 0.25kg, how many nails he have?​
snow_tiger [21]

Answer:

He has 672 nails

Step-by-step explanation:

168/.25

7 0
3 years ago
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Janelle and three of her friends bought four smoothies for a total of $3. If she purchases smoothies on another day for herself
bogdanovich [222]
Janelle will spend $7.50 because each smoothie costs .75 cents.
4 0
3 years ago
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What is the range and domain
mr_godi [17]

Answer:

domain is 0 to infinity and range is 5 to infinity

Step-by-step explanation:

x is domain and y is range

3 0
3 years ago
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A line tangent to the curve f(x)=1/(2^2x) at the point (a, f(a)) has a slope of -1. What is the x-intercept of this tangent?
kirza4 [7]

Answer:

x-intercept = 0.956

Step-by-step explanation:

You have the function f(x) given by:

f(x)=\frac{1}{2^{2x}}   (1)

Furthermore you have that at the point (a,f(a)) the tangent line to that point has a slope of -1.

You first derivative the function f(x):

\frac{df}{dx}=\frac{d}{dx}[\frac{1}{2^{2x}}]  (2)

To solve this derivative you use the following derivative formula:

\frac{d}{dx}b^u=b^ulnb\frac{du}{dx}

For the derivative in (2) you have that b=2 and u=2x. You use the last expression in (2) and you obtain:

\frac{d}{dx}[2^{-2x}]=2^{-2x}(ln2)(-2)

You equal the last result to the value of the slope of the tangent line, because the derivative of a function is also its slope.

-2(ln2)2^{-2x}=-1

Next, from the last equation you can calculate the value of "a", by doing x=a. Furhtermore, by applying properties of logarithms you obtain:

-2(ln2)2^{-2a}=-1 \\\\2^{2a}=2(ln2)=1.386\\\\log_22^{2a}=log_2(1.386)\\\\2a=\frac{log(1.386)}{log(2)}\\\\a=0.235

With this value you calculate f(a):

f(a)=\frac{1}{2^{2(0.235)}}=0.721

Next, you use the general equation of line:

y-y_o=m(x-x_o)

for xo = a = 0.235 and yo = f(a) = 0.721:

y-0.721=(-1)(x-0.235)\\\\y=-x+0.956

The last is the equation of the tangent line at the point (a,f(a)).

Finally, to find the x-intercept you equal the function y to zero and calculate x:

0=-x+0.956\\\\x=0.956

hence, the x-intercept of the tangent line is 0.956

5 0
3 years ago
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