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vesna_86 [32]
3 years ago
14

Over the past several years, the proportion of one-person households has been increasing. The Census Bureau would like to test t

he hypothesis that the proportion of one-person households exceeds 0.27. A random sample of 125 households found that 43 consisted of one person. To conduct the hypothesis test, what distribution would you use to calculate the critical value and the p-value?
a. the Student's t-distribution with 124 degrees of freedom
b. the Student's t-distribution with 125 degrees of freedom
c. the standard normal distribution
d. the Student's t-distribution with 42 degrees of freedom
Mathematics
1 answer:
White raven [17]3 years ago
6 0

Answer:

a. the Student's t-distribution with 124 degrees of freedom

Step-by-step explanation:

We have no information about the standard deviation of the population, just for the sample, which means that the student's t-distribution is used.

Degrees of freedom

Sample size subtracted by 1.

125 households were sampled.

125 - 1 = 124 degrees of freedom.

So the correct answer is:

a. the Student's t-distribution with 124 degrees of freedom

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Two children own two-way radios that have a maximum range of 3 miles. One leaves a certain point at 1:00 P.M., walking due north
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Answer:

The answer is 21 minutes

Step-by-step explanation:

We use the equation Xf = Xo + vt

1) At 1:00 PM, child one leaves the starting point heading north at a constant velocity of 6 mi/hr or .1 [mi/min] (divide by 60 to convert from [mi/hr] to [mi/min])

2) He walks for 15 minutes before kid 2 starts walking. In 15 minutes he is able to cover 1.5 [mi]

  • x_{1f1} =x_{o} +v_{1} t_{1} \\x_{1f1} =0+.1(15)\\x_{1f1} =1.5 [mi]

3) Now, child 2 starts walking and we know that when the range reaches 3 miles, they won´t be able to communicate. So the sum of the final position of child 1 and child 2 must be 3[mi]

  • Child 1 final position => x_{1f} = x_{1f1} +v_{1} t\\x_{1f} =1.5+v_{1} t
  • Child 2 final position => x_{2f} =0+v_{2} t

4) Sum the equations and equate to 3

  • x_{1f} +x_{2f} =3

5) Substitute the values we already know

  • 1.5+v_{1} t+v_{2}t=3\\ 1.5+.1t+.15t=3\\1.5+.25t=3\\t=\frac{3-1.5}{.25} \\t=6 [min]

6) in 15 + 6 minutes they will be 3miles apart

7) In 21 minutes they will still be able to communicate with one another.

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Answer:

I think grater then?

Step-by-step explanation:

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saveliy_v [14]
97% of 11 is:

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The enlargement factor is 1.8

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Answer:

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Step-by-step explanation:

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