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Svet_ta [14]
4 years ago
15

A construction company has an expenditure rate of ​E(x)equalse Superscript 0.11 x dollars per day on a particular paving job and

an income rate of ​I(x)equals116.8 minus e Superscript 0.11 x dollars per day on the same​ job, where x is the number of days from the start of the job. The​ company's profit on that job will equal total income less total expenditures. Profit will be maximized if the job ends at the optimum​ time, which is the point where the two curves meet. ​(a) Find the optimum number of days for the job to last. ​(b) Find the total income for the optimum number of days. ​(c) Find the total expenditures for the optimum number of days. ​(d) Find the maximum profit for the job.

Mathematics
1 answer:
dmitriy555 [2]4 years ago
6 0

Answer:

Check the explanation

Step-by-step explanation:

Kindly check the attached images below to see the step by step explanation to the question above.

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Answer:

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Step-by-step explanation:

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We know the rule of addition is that adding two positive integers will give positive result or sum.

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Step-by-step explanation:

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8 0
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Read 2 more answers
Reading proficiency: An educator wants to construct a 99.5% confidence interval for the proportion of elementary school children
Shkiper50 [21]

Answer:

A sample size of 345 is needed so that the confidence interval will have a margin of error of 0.07

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

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The margin of error of the interval is given by:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

In this problem, we have that:

p = 0.69

99.5% confidence level

So \alpha = 0.005, z is the value of Z that has a pvalue of 1 - \frac{0.005}{2} = 0.9975, so Z = 2.81.

Using this estimate, what sample size is needed so that the confidence interval will have a margin of error of 0.07?

This is n when M = 0.07. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.07 = 2.81\sqrt{\frac{0.69*0.31}{n}}

0.07\sqrt{n} = 1.2996

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A sample size of 345 is needed so that the confidence interval will have a margin of error of 0.07

4 0
3 years ago
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aleksandrvk [35]

Answer:

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