Describe the procedure you performed to derive the slope intercept form of a linear equation

1 answer:

4 0

The slope intercept form a linear equation has the form
y = mx + b

In getting the slope-intercept form of a linear equation, the following should be present: Slope (m) and the x-intercept (b).

If you are given only two coordinates or two points, the the steps are:
1. Get the slope (m) using the formula m = (Y1-Y2) / (X1-X2).
2. Get the x-intercept (b) by substituting any of the two points to the slope-intercept equation.

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Solve for the zeros of the quadratic function f(x) = 9x² + 6x + 1.

Nezavi [6.7K]

Answer:

$\large\boxed{x=-\dfrac{1}{3}}$

Step-by-step explanation:

$f(x)=9x^2+6x+1\\\\\text{The zeros are for}\ f(x)=0\\\\9x^2+6x+1=0\\\\9x^2+3x+3x+1=0\\\\3x(3x+1)+1(3x+1)=0\\\\(3x+1)(3x+1)=0\\\\(3x+1)^2=0\iff3x+1=0\qquad\text{subtract 1 from both sides}\\\\3x=-1\qquad\text{divide both sides by 3}\\\\x=-\dfrac{1}{3}$

8 0

3 years ago

The weight of a radioactive isotope was 96 grams at the start of an experiment. After one hour, the weight of the isotope was ha

zimovet [89]

The starting weight of the radioactive isotope = 96 grams

Weight after one hour is half of the starting weight. So the weight of the radioactive isotope after 1 hour = 48 grams

After 2 hours the weight is half as compared to the weight after previous hour. So weight after 2 hours = 24 grams.

This means, after every hour the weight is being halved. The half life of radioactive isotope is one hour.

Since after every hour, the weight is being halved, the weight of the isotope can be modeled by an exponential equation.

So,

Initial Weight = W₁ = 96
Change factor = 1/2 = 0.5

The general equation of the sequence will be:

$\\ \\ W_{t}=96(0.5)^{t}$

Here t represents the number of hours. Using various values of t we can find the weight of the radioactive isotope at that time.

We can plot the sequence using the above equation. The graph is attached below.