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saul85 [17]
3 years ago
11

PLS HELP 100 POINTS ILL EVEN SEND U 50 AFTER IF U HELP

Mathematics
1 answer:
astraxan [27]3 years ago
6 0

Answer:

1.dd

2.Dd

3.dd

4.Dd

5.dd

Explanation:

It's genetics

   D     d

d   D     d

d   D     d

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3x+8=2x+21<br> X=?<br> (all working out needed)
Dahasolnce [82]

Answer:

x=13

Step-by-step explanation:

3x=2x+21−8

3x=2x+13

3x−2x=13

x=13

8 0
3 years ago
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Can anyone help me plz?
RUDIKE [14]

Answer:

The answer is 37

Step-by-step explanation:

8x8=64

9x3=27

64-27=37

8 0
3 years ago
A car dealership sells 0, 1, or 2 luxury cars on any day. When selling a car, the dealer also tries to persuade the customer to
melisa1 [442]

Answer:

Mean = 1.42

Variance = 0.58

Step-by-step explanation:

Given: X denote the number of luxury cars sold in a given day, and Y denote the number of extended warranties sold.

Also, joint probability function of X and Y are given.

To find:

mean and variance of X

Solution:

From the given joint probability function of X and Y,

P(X=0)=\frac{1}{6}\\P(X=1)=\frac{1}{12}+\frac{1}{6}=\frac{1+2}{12}=\frac{3}{12}\\P(X=2)=\frac{1}{12}+\frac{1}{3}+\frac{1}{6}=\frac{1+4+2}{12}=\frac{7}{12}

Mean of X:

E(X)=\sum XP(X)\\=0\left ( \frac{1}{6} \right )+1\left ( \frac{3}{12} \right )+2\left ( \frac{7}{12} \right )\\=0+\frac{3}{12}+\frac{14}{12}\\=\frac{17}{12}=1.42

Variance of X:

E(X^2)=\sum X^2P(X)\\=0^2\left ( \frac{1}{6} \right )+1^2\left ( \frac{3}{12} \right )+2^2\left ( \frac{7}{12} \right )\\=0+\frac{3}{12}+\frac{28}{12}\\=\frac{31}{12}

var(X)=E\left [ X^2 \right ]-\left ( E\left [ X \right ] \right )^2\\=\frac{31}{12}-\left ( \frac{17}{12} \right )^2\\=\frac{31}{12}-\frac{289}{144}\\=\frac{372-289}{144}\\=\frac{83}{144}\\=0.58

5 0
3 years ago
PLEASE HELP!!! BRAINLIESt!! THANK YOUU
vredina [299]

Answer:

ok

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
A jar contains black marbles and green marbles. Sixty percent of the marbles in the jar are green. A number generator simulates
Natali5045456 [20]

Answer:

The number generator is not fair. In most of the experiments, considerably less than 60% of the selected marbles are green.

Step-by-step explanation:

Run a significant number of times, a fair distribution should be a bell curve  centered on the 6 for 60%

7 0
2 years ago
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