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3 years ago

What is 3m-7n=p for m

Mathematics

1 answer:

Tatiana [17]3 years ago

7 0

3m - 7n = p

Add 7n to each side: 3m = p + 7n

Divide each side by 3 : m = (p + 7n) / 3

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30/19 as a mixed number

Musya8 [376]

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3 years ago

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The jeweler buys gold for 1235.55 per ounce and resells it for 1376.44 per ounce how much profit does the jeweler make from buyi

AnnZ [28]

Profit made by jeweler from buying and reselling ounces of gold is 140.89 per ounce

<u>Solution:</u>

Given that

Price at which jeweler buy gold = 1235.55 per ounce

Price at which jeweler resells gold = 1376.44 per ounce

We need to calculate profit.

Buying price of 1 ounce of gold = 1235.55

Reselling price of 1 ounce of gold = 1376.44

<em>Profit = Reselling price – buying price</em>

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3 years ago

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Step-by-step explanation:

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2 years ago

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The combustion of one gallon of automobile fuel produces about 5 pounds of carbon (in CO₂). Two autos are making a trip of 600 m

rewona [7]

Answer:

Approximately 50 pounds less carbon (in CO₂) will be produced by the second auto on this trip.

Step-by-step explanation:

We have been given that the combustion of one gallon of automobile fuel produces about 5 pounds of carbon (in CO₂). Two autos are making a trip of 600 miles.

Let us find amount of fuel used by autos by dividing the total distance by their mileage.

$\text{Fuel used by 1st auto}=\frac{\text{ 600 miles}}{\frac{\text{ 20 miles}}{\text{gallon}}}$

$\text{Fuel used by 1st auto}=\frac{\text{ 600 miles}}{\text{ 20 miles}}\times \text{gallon}$

$\text{Fuel used by 1st auto}=30 \text{ gallons}$

$\text{Fuel used by 2nd auto}=\frac{\text{ 600 miles}}{\frac{\text{ 30 miles}}{\text{gallon}}}$

$\text{Fuel used by 2nd auto}=\frac{\text{ 600 miles}}{\text{ 30 miles}}\times \text{gallon}$

$\text{Fuel used by 2nd auto}=20 \text{ gallons}$

Let us find the difference of fuel used by both autos.

$\text{Number of gallons that 2nd auto used less than 1st auto}=30-20$

$\text{Number of gallons that 2nd auto used less than 1st auto}=10$

Since one gallon of automobile fuel produces about 5 pounds of carbon, so 10 gallons of fuel will produces $5\times 10=50$ pounds of carbon.

Since 2nd auto used 10 gallons less than 1st auto, therefore, 2nd auto will produce 50 pounds less carbon than 1st auto.

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