I completely forgot how to do this but maybe multiply the angles I’m so sorry
First we need to find the gradient of K
which is y1-y2/x1-x2
(-1,3) and (5,-2)
so it becomes 3-(-2)/-1-5
m=-5/6
when two lines are perpendicular their gradients multiply to make -1
that means the gradient of L has to be 6/5
we can substitute the point on L (5,-2) and the gradient of 6/5 into y=mx+c
-2 = (6/5) x 5 + c
c = -8
the equation of line L is y= 6x/5 -8
Answer:
5x^2-12x-2
Step-by-step explanation:
Use distributive property, then add like terms. See file below for steps.
The formula of a slope:

We have the points (1, 4) and (1, -3). Substitute:

DIVISION BY ZERO!!!
Answer: The slope is undefined.
It's a vertical line x = 1.
Y = -3x + b
Plug in points
4 = -3(-2) + b
4 = 6 + b, b = -2
Solution: y = -3x - 2