This is a strange question, and f(x) may not even exist. Why do I say that? Well..
[1] We know that f(a+b) = f(a) + f(b). Therefore, f(0+0) = f(0) + f(0). In other words, f(0) = f(0) + f(0). Subtracting, we see, f(0) - f(0) = f(0) or 0 = f(0).
[2] So, what's the problem? We found the answer, f(0) = 0, right? Maybe, but the second rule says that f(x) is always positive. However, f(0) = 0 is not positive!
Since there is a contradiction, we must either conclude that the single value f(0) does not exist, or that the entire function f(x) does not exist.
To fix this, we could instead say that "f(x) is always nonnegative" and then we would be safe.
Answer:
2/5
Step-by-step explanation:
3/8 = 375/1000
1/2 = 500/1000
2/5 = 400/1000
Answer:
The answer is A
Step-by-step explanation:
Thinking about the graph of f(x), the rate of change is zero whenever there is an extremum.
First, differentiate f(x)

Next, find the zeros of f'(x) by factoring.

Now, we substitute these x-values into the
original equation to find the coordinates.
(-2.667, 11.481), (0, 2)
Answer:
a = 8
Step-by-step explanation:
4 : 3 = a : 6

Cross multiply
4*6 = a * 3

a = 4 * 2
a = 8