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DENIUS [597]
3 years ago
12

Given the equation y = 3x + 2 , what is the value of x when y = 8? A:2 B:4 C:6 D:9

Mathematics
1 answer:
stiv31 [10]3 years ago
3 0

Answer:

a

Step-by-step explanation:

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John has 12 marbles of different colors, including one red, one green, and one blue marble. in how many ways can he choose 4 mar
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3 ways (uncertain)
1 red or blue or green + 3 other colours
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3 years ago
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Find the value of n and yz if y is between x and z. xy = 4n 3. yz = 2n-7, xz = 20 yz = need help with this question?
Helga [31]

The value of n is 4 and yz is 1 if y is between x and z i.e. if y, x and z are collinear points.

According to the given question.

We have some linear equations.

xy = 4n + 3

yz = 2n - 7

and

xz = 20

Since, y is between x and z. Which means y, x and z are collinear points.

Therefore,

xy + yz = xz

⇒ 4n + 3 + 2n - 7 = 20

⇒ 6n -4 = 20

⇒ 6n = 20 + 4

⇒ 6n = 24

⇒ n = 24/6

⇒ n = 4

Therefore,

yz = 2n - 7 = 2(4) - 7 = 8- 7 = 1

Hence, the value of n is 4 and yz is 1 if y is between x and z i.e. if y, x and z are collinear points.

Find out more information about collinear points here:

brainly.com/question/1593959

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3 0
1 year ago
A boat costs $14,000 and decreases in value by 5% per year. How much will the boat be worth after 3 years?
kati45 [8]

Answer:

$12,003.25.

Step-by-step explanation:

The boat's values after each year is  $14,000 * (100-5)%, so

the equation is A = 14000(0.95)^3

= $12,003.25.

8 0
2 years ago
A game is played as follows:
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This game is not fair. No one will know wha their going to get. It is a game of probability
4 0
3 years ago
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Points M, N, and P are respectively the midpoints of sides AC , BC , and AB of △ABC. Prove that the area of △MNP is on fourth of
Hunter-Best [27]

Answer:

The area of △MNP is one fourth of the area of △ABC.

Step-by-step explanation:

It is given that the points M, N, and P are the midpoints of sides AC, BC and AB respectively. It means AC, BC and AB are median of the triangle ABC.

Median divides the area of a triangle in two equal parts.

Since the points M, N, and P are the midpoints of sides AC, BC and AB respectively, therefore MN, NP and MP are midsegments of the triangle.

Midsegments are the line segment which are connecting the midpoints of tro sides and parallel to third side. According to midpoint theorem the length of midsegment is half of length of third side.

Since MN, NP and MP are midsegments of the triangle, therefore the length of these sides are half of AB, AC and BC respectively. In triangle ABC and MNP corresponding side are proportional.

\triangle ABC \sim \triangle NMP

MP\parallel BC

MP=\frac{BC}{2}

By the property of similar triangles,

\frac{\text{Area of }\triangle MNP}{\text{Area of }\triangle ABC}=\frac{PM^2}{BC^2}

\frac{\text{Area of }\triangle MNP}{\text{Area of }\triangle ABC}=\frac{(\frac{BC}{2})^2}{BC^2}

\frac{\text{Area of }\triangle MNP}{\text{Area of }\triangle ABC}=\frac{1}{4}

Hence proved.

5 0
3 years ago
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