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3 years ago

Given an example of a line that is parallel to y = 3x - 4

Mathematics

2 answers:

galina1969 [7]3 years ago

8 0

Answer:

y=3x-1

Step-by-step explanation:

y-intercept can be any numbers

olga_2 [115]3 years ago

6 0

Answer:

? i had this but forgot it sorry

Step-by-step explanation:

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Need help ASAP!! I'll give brainliest to correct answer!!!

erastovalidia [21]

Step-by-step explanation:

so...the answer is C.27.7m

4 0

3 years ago

Read 2 more answers

The cost of a council tax bill increased by 5%.

andreyandreev [35.5K]

The council tax bill before the increase is £1240

The equation that represents the percentage increase in council tax bill is :

percentage increase x t = £62

Where t represents the initial council tax bill - council tax bill before the 5% increase

5% x t = £62

0.05 x t = £62

Divide both sides of the equation by 0.05

t = £62 / 0.05 = £1240

To check if the answer derived is correct : 5% x 1240 = 62.

A similar question was answered here: brainly.com/question/12066598?referrer=searchResults

5 0

3 years ago

A driver travels a distance of 119 miles between 09:50 and 11:35. Work out the average speed of the driver

AURORKA [14]

Answer:

68 miles per hour.

Step-by-step explanation:

The time taken for the driver to drive 119 miles is 105 minutes.

The average speed is equal to distance divided by the time taken.

105 minutes is equal to 1.75 hours.

$S=119/1.75$

$S =68$

The driver's average speed is 68 miles per hour.

7 0

3 years ago

Read 2 more answers

Suppose that D(r) is a function which gives the population density, in hundreds of people per square mile, within r miles of the

borishaifa [10]

Answer:

a) T(r) = r.D(r)

b) 975 people per square mile.

Step-by-step explanation:

(a)

The units of D(r) are

$\frac{hundreds\;of\;people}{mile^2}$

when multiplying the density by the area we get the amount of people in that area, so

$T(r)=rmile^2D(r)\frac{hundreds\;of\;people}{mile^2}=rD(r)\;hundreds\;of\;people$

(b)

The average rate of change of T(r) over the interval [5,7] is

$\frac{T(7)-T(5)}{7-5}=\frac{7D(7)-5D(5)}{2}$

but D(7) = 350 and D(5) = 100, so

$\frac{7D(7)-5D(5)}{2}=\frac{7*350-5*100}{2}=975$

and the average rate of change of T(r) over the interval [5,7] is 975 people per square mile.

5 0

4 years ago

In 1985, there was 285 cell phones subscribers in the small town of centerville.After 1985, the number of subscribers increased

wolverine [178]

First we write a function that suits the problem.
We have then:
y = 285 * (1.75) ^ x
Then, we see how many years there are in the requested period
x = 1994-1985 = 9
We evaluate the function for x = 9
y = 285 * (1.75) ^ 9
y = 43871.98637
Round nearest whole number
y = 43872
Answer:
there were 43872 cell phones subscribers in centerville in 1994

4 0

3 years ago