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4 years ago

PLEASE

Mathematics

2 answers:

vaieri [72.5K]4 years ago

8 0

Answer:

Answer would be 0.67 years, 13.3 years and 1.5 years.

Step-by-step explanation:

It is given Mean = 13.3, Median = 13.5, Mode = 14, MAD = 0.67

Now we complete each statement from the given data.

Here Mean absolute Deviation is 0.67 which shows how far or how near the values to the mean value.

1. On average, the age of a student is about 0.67 year(s) away from 13.3 year(s).

2. If the MAD for another club was 1.5 years, then that club's ages would be 1.5 than the ages for this club.

blsea [12.9K]4 years ago

3 0

On average, the age of a student is about .67 year(s) away from 13.3 year(s).

If the MAD for another club was 1.5 years, then that club's ages would be 3 more variable than the ages for this club.

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Tiffany started a doggle daycare where she offered a variety of services, including grooming. She charges an hourly rate of

puteri [66]

The linear function in slope-intercept form for the cost of a visit of x hours is given as follows:

C(x) = 9x + 31.

<h3>What is a linear function?</h3>

A linear function is modeled by:

y = mx + b

In which:

m is the slope, which is the rate of change, that is, by how much y changes when x changes by 1.

b is the y-intercept, which is the value of y when x = 0, and can also be interpreted as the initial value of the function.

In this problem, the rate means that the slope is of m = 9. When x = 3, C(x) = 58, hence the y-intercept is found as follows:

C(x) = 9x + b

58 = 9(3) + b

b = 31.

Hence the equation is:
C(x) = 9x + 31.

More can be learned about linear functions at brainly.com/question/24808124

#SPJ1

7 0

2 years ago

The half-life of a certain radioactive material is 38 days. An initial amount of the material has a mass of 497 kg. Write an exp

rjkz [21]

It is the 1st equation at the top.

Reason: First check the equations to check that the initial amount is 497 kg. You can do this by setting x = 0 into all of the equations. The 3rd and 4th equations evaluate to 2 when x = 0 and so you can eliminate the bottom 2 equations immediately. Equation # 2 does not work since the half-life value of 1.040 kg is way to small (significantly smaller than half of 497 kg).

You can check that equation # 1 is the right one, by setting x = 0 and getting

y = 497*(1/2)^[(1/38) * 0] = 497

so the initial amount is 497

Also check that there is 1/2 the amount at time 38 (since the half-life is 38 days)

y = 497 * (1/2)^[(1/38) * 38] = 248.5

248.5 kg is half of 497 and so this checks out for equation # 1.

Since we know equation # 1 is good, now we evaluate at x = 4 to get

y = 497 * (1/2)^[(1/38) * 4] = 462.029

so our answer to the thousandth places is 462.029 kg.

6 0

4 years ago

A formula is expressed as d=a(2+kt). Express k in terms of d, a and t

taurus [48]

Answer:
k = $\frac{d-2a}{at} = \frac{d}{at} - \frac{2a}{at} = \frac{d}{at} - \frac{2}{t}$ 

Explanation:
To get the value of k, we will need to isolate it on one side of the equation.
This can be done as follows:
d = a(2+kt)

1- get rid of the brackets using distributive property:
d = a(2+kt)
d = 2a + akt

2- Subtract 2a from both sides of the equation:
d - 2a = 2a + akt - 2a
d - 2a = akt

3- Divide both sides of the equation by "at":
 $\frac{d-2a}{at} = \frac{akt}{at}$ 

 $k= \frac{d-2a}{at}$

4- We can further simplify the answer as follows:
k = $\frac{d-2a}{at} = \frac{d}{at} - \frac{2a}{at} = \frac{d}{at} - \frac{2}{t}$

Hope this helps :)

7 0

3 years ago

Read 2 more answers

Find the value of f(5) for the function. f(a) = 4(a + 4) - 3

MrRissso [65]

Answer:

$f(a) = 4(a + 4) - 3 = 4a + 16 - 3 \\ f(x) = 4a + 13 \\ f(5) = 4(5) + 13 = 20 + 13 \\ \boxed{f(5) = 33}$

<h2>33 is the right answer.</h2>

3 0

3 years ago

Four friends are standing in line to buy tickets. Carlos is not first in line. Paige is ahead of Kate. Lisa is last in line.

DiKsa [7]

Well Carlos obviously isn't first, and the question states that Lisa is last.
And Paige is in front of Kate, so the line would go:

Paige
Kate
Carlos
Lise

4 0

3 years ago