centre = ( - 9, 6)
the equation of a circle in standard form is
(x - a)² + (y - b)² = r²
where (a , b) are the coordinates of the centre and r is the radius
(x + 9)² + (y - 6)² = 102 is in this form
with centre = ( - 9 , 6 )
Answer: X=4
Step-by-step explanation:
Pulling out like terms :
1.1 Pull out like factors :
2x - 8 = 2 • (x - 4)
Equation at the end of step 1 :
Step 2 :
Equations which are never true :
2.1 Solve : 2 = 0
This equation has no solution.
A a non-zero constant never equals zero.
Solving a Single Variable Equation :
2.2 Solve : x-4 = 0
Add 4 to both sides of the equation :
x = 4
One solution was found :
x = 4
1 and they split the other in half
Answer:
115m
Step-by-step explanation:
Note that one of the face of a pyramid is a right angled triangle.
Since the pyramid was about 147m tall, the height of triangle will be 147m. If one of the faces is built with one of its faces at 52° to the incline, we can find the original length of one of its sides using SOH CAH TOA
tan(theta) = opposite/adjacent
Given theta = 52°, opposite = 147m (the side directly opposite the angle)
Substituting we have;
Tan52° = 147/adjacent
Adjacent = 147/tan52°
Adjacent = 114.8m
= 115m
Therefore 115m is the original length of one of its side
Given that,
Radius of the circle, r = 8.91 cm
Angle, 
To find,
The area of minor sector.
Solution,
The formula for the area of minor sector is given by the formula as follows :
So, the area of the shaded sector is 
.
