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Tcecarenko [31]
3 years ago
8

What does N equal? I am stuck and need all the help I can get.

Mathematics
1 answer:
Ksivusya [100]3 years ago
8 0
I'm thinking that n=18 but some parts of the question were cut off so i couldn't quite see it. But this is how I saw it: 4+n/2+2n/n+3=20 and <span>2 to the power of 18-1, so this is what i got. Hope it helps.</span>
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Sloan [31]

Answer:

<h3>#1</h3>

<u>Rectangle area:</u>

  • A = lw

<u>Given:</u>

  • l = 12 ft, A = 300 ft²

<u>Find w:</u>

  • 12w = 300
  • w = 300/12
  • w = 25 ft
<h3>#2</h3>

<u>Perimeter is the sum of side lengths:</u>

P = 2 1/4 + 5 2/5 + 5 17/20 =

     2 + 5 + 5 + 1/4 + 2/5 + 17/20 =

     12 + 5/20 + 8/20 + 17/20 =

     12 + 30/20 =

     12 + 1.5 =

     13.5 ft

<h3>#3</h3>
  • Cost of a shirt = $19.99
  • Number of shirts = 6

<u>Total cost:</u>

  • $19.99*6 = $119.94

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15. There is a 25% chance of rain tomorrow. The probability that the price of gold rises tomorrow is 37%. The probability that i
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Step-by-step explanation:

yes, the 2 events are entirely independent

neither one influences the other.

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The type of number that cannot be expressed as a fraction because the fractional part would go on for infinity without ever repe
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Irrational

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What’s the answer to this please I rlly need it
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Answer:I think its last one sorry if I am wrong

Step-by-step explanation:

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Initially 15 grams of salt are dissolved into 25 liters of water. Brine with concentration of salt 4 grams per liter is added at
Alla [95]

Answer:

a) dx/dt = 600 - 6x

b) x = 100 - 4.12((e⁻ ⁽⁶ᵗ ⁻ ³•⁰²⁾)

c) The mass of salt in the tank attains the value of 20 g at time, t = 0.227 min = 13.62 s

Explanation:

Taking the overall balance, since the total Volume of the setup is constant, then flowrate in = flowrate out

Let the concentration of salt in the tank at anytime be C

Let the concentration of salt entering the tank be Cᵢ

Let the concentration of salt leaving the tank be C₀ = C (Since it's a well stirred tank)

Let the flowrate in be represented by Fᵢ

Let the flowrate out = F₀ = F

Fᵢ = F₀ = F = 6 L/min

a) Then the component balance for the salt

Rate of accumulation = rate of flow into the tank - rate of flow out of the tank

dx/dt = Fᵢxᵢ - Fx

Fᵢ = 6 L/min, C = 4 g/L, F = 6 L/min

dC/dt = 24 - 6C

dx/dt = 25 (dC/dt), (dC/dt) = (1/25) (dx/dt) and C = x/25

(1/25)(dx/dt) = 24 - (6/25)x

dx/dt = 600 - 6x

b) dC/dt = 24 - 6C

dC/(24 - 6C) = dt

∫ dC/(24 - 6C) = ∫ dt

(-1/6) In (24 - C) = t + k (k = constant of integration)

In (24 - 6C) = -6t - 6k

-6k = K

In (24 - 6C) = K - 6t

At t = 0, C = 15 g/25 L = 0.6 g/L

In (24 - 6(0.6)) = K

In 20.4 = K

K = 3.02

So, the equation describing concentration of salt at anytime in the tank is

In (24 - 6C) = K - 6t

In (24 - 6C) = 3.02 - 6t

24 - 6C = e⁻ ⁽⁶ᵗ ⁻ ³•⁰²⁾

6C = 24 - (⁻⁽⁶ᵗ ⁻ ³•⁰²⁾)

C = 4 - ((e⁻⁽⁶ᵗ ⁻ ³•⁰²⁾)/6

C = 4 - (e⁻ ⁽⁶ᵗ ⁻ ³•⁰²⁾)/6)

But C = x/25

x/25 = 4 - (e⁻ ⁽⁶ᵗ ⁻ ³•⁰²⁾)/6)

x = 100 - 4.12((e⁻ ⁽⁶ᵗ ⁻ ³•⁰²⁾)

c) when x = 20 g

20 = 100 - 4.12(e⁻ ⁽⁶ᵗ ⁻ ³•⁰²⁾)

80 = (e⁻ ⁽⁶ᵗ ⁻ ³•⁰²⁾)

- (6t - 3.02) = In 80

- (6t - 3.02) = 4.382

(6t - 3.02) = -4.382

6t = -4.382 + 3.02

t = 1.362/6 = 0.227 min = 13.62 s

4 0
3 years ago
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