
Solution (1)



for k=0 / for k=1 / for k=-1
x=0 / x=2π / x=-2π
acc / acc / rej
solution (2)




for k=0 / for k=1 / for k=-1
x=0 / x=2π/3 / x=-2π/3
acc / acc / rej
Note that i'm trying values of K which make the answer belong to our interval;
So our solution which i will represent as a set is;
S € {0,2π/3,2π}
Answer:
No, they are not equivalent
Step-by-step explanation:

15,785 and well try to do your best haha
So, (6a - X)*5a = Y*(a^2) - 35a
<span>=> 6a*5a - X*5a = Y*(a^2) - 35a </span>
<span>=> 30(a^2) - X*5a = Y(a^2) - 35a
</span>30 = Y and
<span>X*5 = 35 or X = 7 </span>
Divide 8 ft by 0.75, then divide by one third.