Question

find the equation of the line that is perpendicular to the given line and passes through the given point. CD; (-2,1). C cornet point is (2,13). D cornet point is (5,7).

Answer 1

Answer:

  x -2y = -4

Step-by-step explanation:

The slope of the line between points C and D is ...

  m = (y2 -y1)/(x2 -x1)

  m = (7 -13)/(5 -2) = -6/3 = -2

The slope of the perpendicular line is the opposite reciprocal of this: -1/(-2) = 1/2. The point-slope equation of the desired line is ...

  y -k = m(x -h) . . . . line with slope m through point (h, k)

  y -1 = 1/2(x -(-2))

We can rearrange this to standard form.

  2y -2 = x +2 . . . . . multiply by 2

  -4 = x -2y . . . . . . . subtract 2y+2

  x -2y = -4 . . . . . . standard form equation of the desired line