Answer:
plus 4 every time
Step-by-step explanation:
1+4=5+4=9+4=13+4=17
Answer:
Step-by-step explanation:
Let's say that the time it took him to get to work in the morning is t hours. Then the time it took him to get home in the afternoon must be 1 - t hours. We know that for any trip, distance equals rate times time or d = rt . That means that the distance he drove to work is given by , but we also know that the distance he drove to get home must be the same distance, because he took the same route (and, presumably, no one picked up him house and moved it while he was at work) so for the trip home we can say d = 30 × (1 - t) and since the distances are equal, we can say:
45t = 30 × (1 - t)
45t = 30 - 30t
45t + 30t = 30
75t = 30
t = 30/75
t = 2 /5 hour to drive to work at 45mph
Since , d = rt
d = 45 ×(2/5) = 18miles
9514 1404 393
Answer:
60
Step-by-step explanation:
Let m represent the mark Cheryn scored on her first quiz. Then her average is ...
(m +76 +89)/3 ≥ 75
m +165 ≥ 225 . . . . . . . . multiply by 3
m ≥ 60 . . . . . . . . . . . . subtract 165
Cheryn scored a minimum of 60 marks on her first quiz.
Answer:
180
Step-by-step explanation:
What you have to do is multiply all of them.
9 x 4 x 5 = 180
Answer: (751.05, 766.95)
Step-by-step explanation:
We know that the confidence interval for population mean is given by :-
,
where 
=population standard deviation.
= sample mean
n= sample size
z* = Two-tailed critical z-value.
Given : 
n= 42
We know that from z-table , the two-tailed critical value for 99% confidence interval : z* =2.576
Now, the 99% confidence interval around the true population mean viscosity :-
![759\pm (2.5760)\dfrac{20}{\sqrt{42}}\\\\=759\pm (2.5760)(3.086067)\\\\=759\pm7.9497=(759-7.9497,\ 759+7.9497)\]\\=(751.0503,\ 766.9497)\approx(751.05,\ 766.95)](https://tex.z-dn.net/?f=759%5Cpm%20%282.5760%29%5Cdfrac%7B20%7D%7B%5Csqrt%7B42%7D%7D%5C%5C%5C%5C%3D759%5Cpm%20%282.5760%29%283.086067%29%5C%5C%5C%5C%3D759%5Cpm7.9497%3D%28759-7.9497%2C%5C%20759%2B7.9497%29%5C%5D%5C%5C%3D%28751.0503%2C%5C%20766.9497%29%5Capprox%28751.05%2C%5C%20766.95%29)
∴ A 99% confidence interval around the true population mean viscosity : (751.05, 766.95)
