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svetlana [45]
3 years ago
5

Find −1 1/5+(−3/5). Write your answer as a fraction in simplest form. (NO DECIMALS)

Mathematics
1 answer:
Veronika [31]3 years ago
5 0
−1 1/5+(−3/5)
Convert -1 1/5 into improper fraction
-6/5+(-3/5)
Add -3/5 to -6/5. This would be the same as subtracting 3/5 from -6/5
<span>Final Answer: -9/5 or -1 4/5</span>
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FInd the length of a segment that has endpoints H(2,-3) and J(12,7)
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d =sqrt ((x2-x1)^2 +(y2-y1)^2)

sqrt((12-2)^2 +(7--3)^2)

sqrt(10^2+10^2)

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5 0
3 years ago
Simplify 9y+2y-5y please answer
Brums [2.3K]

Answer:

9y+2y-5y=6y

Step-by-step explanation:

So we have the expression:

9y+2y-5y

To simplify, simply combine the like terms. Therefore:

9y+2y-5y\\=11y-5y\\=6y

Further notes:

To understand why we can combine like terms in the first place, we just need to use the distributive property. So we have the expression:

9y+2y-5y

Now, factor out a y from the three terms:

=y(9+2-5)

Do all the operations inside the parenthesis:

y(9+2-5)\\=y(11-5)\\=y(6)=6y

And we moved the y back to the front!

This is the same result as before. When combining like terms, this is what we're essentially doing but without doing the distributive property manually. I hope you understand a bit better on how and why we can combine like terms!

7 0
2 years ago
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What is the domain of this function?
muminat

It's Letter C. 1 3 and 5

that's the domain

8 0
3 years ago
Divide. write each answer in simplest form.
Aleksandr [31]

Answer:

just do cross multiplication

Step-by-step explanation:

then ans will come

5 0
3 years ago
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The graph of which function has an axis of symmetry at x=3?​
iragen [17]

Answer:

A graph that has an axis of symmetry at x = 3 would be x^2 -6x + 12

Step-by-step explanation:

In order to find a graph that has an axis of symmetry at 3, use the equation for the axis of symmetry of a quadratic.

x = -b/2a

In this equation, a is the coefficient of x^2 and b is the coefficient of x. So, if we use 3 as x and we choose a random number to be a (1), we can solve for the b.

3 = -b/2(1)

3 = -b/2

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b = -6

Now that we have this, we can put those two numbers as coefficients. The constant at the end can be anything.

5 0
3 years ago
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